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topjm [15]
2 years ago
14

Write a function named firstLast2 that takes as input an array of integers and an integer that specifies how many entries are in

the array. The function should return true if the array starts or ends with the digit 2. Otherwise it should return false. Test your function with arrays of different length and with the digit 2 at the beginning of the array, end of the array, middle of the array, and missing from the array.
Computers and Technology
1 answer:
frosja888 [35]2 years ago
4 0

Answer:

<em>Written in C++</em>

#include<iostream>

using namespace std;

int firstLast2(int arr[], int n);

int main()

{

int n;

cout<<"Number of Elements: ";

cin>>n;  

int myarray[n];

for(int i = 0; i<n;i++) {

cin>>myarray[i];

}

firstLast2(myarray, n);

return 0;

}

int firstLast2(int arr[], int n){

if(arr[0] == 2 || arr[n - 1] == 2) {

 cout<<"True";

}

else {

cout<<"False";

}

}

Explanation:

<em>I've added the full source code as an attachment where I used comments to explain difficult lines</em>

Download cpp
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Answer:

Go to explaination for the program code.

Explanation:

Before running the program you need to have these files created like below in your unix box.

Unix Terminal> cat nouns.txt

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Unix Terminal> cat prepositions.txt

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Code:

#!/usr/local/bin/python3

import random

def getWords(filename):

fp = open(filename)

temp_list = list()

for each_line in fp:

each_line = each_line.strip()

temp_list.append(each_line)

words = tuple(temp_list)

fp.close()

return words

articles = getWords('articles.txt')

nouns = getWords('nouns.txt')

verbs = getWords('verbs.txt')

prepositions = getWords('prepositions.txt')

def sentence():

return nounPhrase() + " " + verbPhrase()

def nounPhrase():

return random.choice(articles) + " " + random.choice(nouns)

def verbPhrase():

return random.choice(verbs) + " " + nounPhrase() + " " + prepositionalPhrase()

def prepositionalPhrase():

return random.choice(prepositions) + " " + nounPhrase()

def main():

number = int(input('Enter number of sentences: '))

for count in range(number):

print(sentence())

if __name__=='__main__':

main()

kindly check attachment for code output and onscreen code.

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Explanation:

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Read 2 more answers
7.8.1: Function pass by reference: Transforming coordinates. Define a function CoordTransform() that transforms the function's f
Lilit [14]

Answer:

Here is the CoordTransform() function:              

void CoordTransform(int xVal, int yVal, int &xValNew, int &yValNew){

xValNew = (xVal + 1) * 2;

yValNew = (yVal + 1) * 2; }

The above method has four parameters xVal  and yVal that are used as input parameters and xValNew yValNew as output parameters. This function returns void and transforms its first two input parameters xVal and yVal into two output parameters xValNew and yValNew according to the formula: new = (old + 1) *

Here new variables are xValNew  and yValNew and old is represented by xVal and yVal.

Here the variables xValNew and yValNew are passed by reference which means any change made to these variables will be reflected in main(). Whereas variables xVal and yVal are passed by value.

Explanation:

Here is the complete program:

#include <iostream>

using namespace std;

void CoordTransform(int xVal, int yVal, int &xValNew, int &yValNew){

xValNew = (xVal + 1) * 2;

yValNew = (yVal + 1) * 2;}

int main()

{ int xValNew;

int yValNew;

int xValUser;

int yValUser;

cin >> xValUser;

cin >> yValUser;

CoordTransform(xValUser, yValUser, xValNew, yValNew);

cout << "(" << xValUser << ", " << yValUser << ") becomes (" << xValNew << ", " << yValNew << ")" << endl;

return 0; }

The output is given in the attached screenshot   

7 0
2 years ago
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