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aivan3 [116]
2 years ago
15

On a coordinate plane, 2 lines are shown. Line P Q has points (negative 5, 3) and (5, 1). Line R S has points (negative 4, negat

ive 2) and (0, negative 4).
Which statement best explains the relationship between lines PQ and RS?
They are parallel because their slopes are equal.
They are parallel because their slopes are negative reciprocals.
They are not parallel because their slopes are not equal.
They are not parallel because their slopes are negative reciprocals.

Mathematics
2 answers:
Doss [256]2 years ago
8 0

Answer:

the correct answer is c

Step-by-step explanation:

Edu2020

Romashka-Z-Leto [24]2 years ago
3 0

Given:

Line P Q has points (-5, 3) and (5, 1).

Line R S has points (-4, -2) and (0, -4).

To find:

The relationship between lines PQ and RS.

Solution:

If a line passing through two points, then the slope of line is

m=\dfrac{y_2-y_1}{x_2-x_1}

Line P Q has points (-5, 3) and (5, 1). So, slope of line PQ is

m_1=\dfrac{1-3}{5-(-5)}

m_1=\dfrac{-2}{5+5}

m_1=\dfrac{-2}{10}

m_1=\dfrac{-1}{5}

Line R S has points (-4, -2) and (0, -4). So, slope of line RS is

m_2=\dfrac{-4-(-2)}{0-(-4)}

m_2=\dfrac{-4+2}{0+4}

m_2=\dfrac{-2}{4}

m_2=\dfrac{-1}{2}

Slopes of two parallel lines are equal.

m_1\neq m_2

They are not parallel because their slopes are not equal.

Therefore, the correct option is C.

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An astronaut on the moon throws a baseball upward. The astronaut is 6 ft, 6 in. tall, and the initial velocity of the ball is 40
satela [25.4K]

Answer:

0.14 s

Step-by-step explanation:

s = -2.7 t² + 40t + 6.5

Let s = 12

12 = -2.7t² + 40t + 6.5     Subtract 12 from each side

-2.7t² + 40t + 6.5 - 12 = 0

      -2.7t² + 40t - 5.5 = 0

Apply the <em>quadratic formula </em>

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

a = -2.7; b = 40; c = -5.5

x = \frac{-40\pm\sqrt{40^2 - 4\times (-2.7) \times (-5.5)}} {2(-2.7)}

x = \frac{-40\pm\sqrt{1600-59.4}}{-5.4}

x = \frac{-40\pm\sqrt{1540.6}}{-5.4}

x = \frac{-40\pm 39.25}{-5.4}

x = 7.41 ± 7.27

x₁ = 0.14; x₂ = 14.68

The graph below shows the roots at x₁ = 0.134 and x₂ = 14.68.

The Moon’s surface is at -12 ft. The ball will be 12 ft above the Moon’s surface (crossing the x-axis) in 0.14 s.

The second root gives the time the ball will be 12 ft above the Moon’s surface on its way back down.

6 0
2 years ago
Joey is buying plants for his garden. He wants to have at least twice as many flowering plants as nonflowering plants and a mini
vodomira [7]
(24, 12) and (36, 0).  The least amount of flowering plants occurs when x=2y, and the largest amount occurs when y=0.  These two points satisfy both conditions and both sum to 36.
7 0
2 years ago
Read 2 more answers
Malachy, Gavin and Gavyn share £18 in a ratio 3:1:2. How much money does each person get?
Drupady [299]

Answer:

6

Step-by-step explanation:

18×(3/6) = 918×(1/6) = 318×(2/6) = 6

7 0
2 years ago
Jeremy rides his bike at a rate of 15 miles per hour. Below is a table that represents the number of hours and miles Kevin rides
TiliK225 [7]

The correct answer would be, Jeremy rides at a greater speed than Kevin.

Step-by-step explanation:

Jeremy rides at a rate of 15 miles per hour

Kevin rides at a rate given in the table

Let Y be the distance traveled by Jeremy

And X be the number of hours

Then for Jeremy:

y/x = 15/1

=> y= 15 x

For Kevin:  

(46-23)/(4-2)

= 23/2

= 11.5

So for Kevin, Y = 11.5 x

So when Jeremy's and Kevin's rates are compared,

15 > 11.5

which means Jeremy rides at a greater speed.  

Learn more about Time and Distance problem at:

brainly.com/question/3581191

#LearnWithBrainly

3 0
2 years ago
What’s the 38th term of the arithmetic sequence 31,40,49,58?
Trava [24]

Answer:

a_3_8=364

Step-by-step explanation:

we know that

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant, and this constant is called the common difference

we have

31,40,49,58,...

Let

a_1=31\\a_2=40\\a_3=49\\a_4=58

we have that

a_2-a_1=40-31=9

a_3-a_2=49-40=9

a_4-a_3=58-49=9

so

The common difference is equal to 9

We can write an Arithmetic Sequence as a rule:

a_n=a_1+d(n-1)

where

a_n is the nth term                                                              

a_1 is the first term

d is the common difference                        

n is the number of terms

Find the 38th term of the arithmetic sequence

we have                  

a_1=31\\d=9\\n=38              

substitute the values

a_3_8=31+9(38-1)

a_3_8=31+9(37)

a_3_8=364

3 0
2 years ago
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