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Bad White [126]
2 years ago
7

Given: Line segment N M is parallel to line segment P O. and Angle 1 is-congruent-to angle 3 Prove: Line segment N M is parallel

to line segment N O. 4 lines are connected. Line segment L M connects to line segment M N to form angle 1. Line segment M N connects to line segment N O to form angle 2. Line segment N O connects to line segment O P to form angle 3. A 2-column table has 5 rows. Column 1 is labeled statements with the entries line segment N M is parallel to line segment P O, angle 2 is-congruent-to angle 3, angle 1 is-congruent-to angle 3, angle 1 is-congruent-to angle 2, line segment L M is parallel to line segment N O. What is the missing reason in the proof?
Mathematics
1 answer:
Elina [12.6K]2 years ago
3 0

Answer:

C

Step-by-step explanation:

The proof would be the same as statement 2 as the conditions are the same.

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Frank left his house at 7 a.m. and drove to the airport at a speed of 50 mph. Lance left his house at 6 a.m. and drove to the sa
Tamiku [17]

Answer:

Lance will arrive at the airport at 10:00 AM.

Step-by-step explanation:

Lance left his house at 6:00 AM, and drove to the airport, which is 220 miles away, at 55mph; therefore, the time t it takes Lance to cover the distance of 220 miles is

t = \dfrac{220m}{55mph}

t= 4 \: hours.

Thus, it takes Lance 4 hours to reach the airport, and since he departed at 6:00 AM, he will arrive at the airport at (6+4):00 AM + 10:00 AM.

6 0
2 years ago
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Choose the correct simplification of (3x3 + 2x2 − 5x) − (8x3 − 2x2)
zmey [24]
(3x³ + 2x² - 5x) - (8x³ - 2x²<span>) =
</span>3x³ + 2x² - 5x - 8x³ + 2x² =
-5x³ + 4x² - 5x
5 0
2 years ago
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Given: Circle X with a Radius r and circle Y with radius s Prove: Circle x is similar to circle y
lana [24]

Two figures are similar if one is the scaled version of the other.

This is always the case for circles, because their geometry is fixed, and you can't modify it in anyway, otherwise it wouldn't be a circle anymore.

To be more precise, you only need two steps to prove that every two circles are similar:

  1. Translate one of the two circles so that they have the same center
  2. Scale the inner circle (for example) unit it has the same radius of the outer one. You can obviously shrink the outer one as well

Now the two circles have the same center and the same radius, and thus they are the same. We just proved that any two circles can be reduced to be the same circle using only translations and scaling, which generate similar shapes.

Recapping, we have:

  1. Start with circle X and radius r
  2. Translate it so that it has the same center as circle Y. This new circle, say X', is similar to the first one, because you only translated it.
  3. Scale the radius of circle X' until it becomes s. This new circle, say X'', is similar to X' because you only scaled it

So, we passed from X to X' to X'', and they are all similar to each other, and in the end we have X''=Y, which ends the proof.

8 0
2 years ago
Read 2 more answers
PLS HALP ME!!!!!! You have $6.50 to make copies. Each copy costs $0.45. Write and solve an inequality that represents the number
serious [3.7K]

Step-by-step explanation:

Variable x = number of copies

6.50 <= 0.45x

Divide both sides by 0.45

6.50 ÷ 0.45 <= 0.45x ÷ 0.45

14.4444.... <= x

No more than 14 copies

6.50 <= 0.45x

6.50 <= 0.45(14.444)

7 0
2 years ago
Find the coordinates of the midpoint of LB if L(8,5) and B(-6,2)<br><br> 10 points!!!
KATRIN_1 [288]

Answer:

A, (1, 3+1/2)

Step-by-step explanation:

Midpoint formula for reference: m= {(x1 + x2)/2, (y1 + y2)/2}

Plugging in the points we get: m= {(8 - 6)/2, (5 + 2)/2}

Now we simplify using PEMDAS. First step is parentheses.

m= {2/2, 7/2}

Simplifying again (and making 7/2 a mixed number), it becomes

m= {1, 3+1/2}

Hope this helps!

3 0
1 year ago
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