Sarah has to add a picture from her computer file and add a caption to it. Arrange the steps in a correct sequence.

Write a function called add_tuples that takes three tuples, each with two values, and returns a single tuple with two values con

Leni [432]

In Python, tuples are indeed a data structure that also stores an ordered sequence of unchanging values, and following are the Python program to the given question:

Program Explanation:

Defining a method "add_tuples" that takes three variables "firstTuple, secondTuple, thirdTuple" into the parameter.
After accepting the parameter value a return keyword is used that adds a single tuple with two values and returns its value into the form of (x,y).
Outside the method, two print method is declared that calls the above method by passing value into its parameters.

Program:

def add_tuples(firstTuple, secondTuple, thirdTuple):#defining a method add_tuples that takes three variable in parameters

return firstTuple[0]+secondTuple[0]+thirdTuple[0],firstTuple[1]+secondTuple[1]+thirdTuple[1] #using return keyword to add value

print(add_tuples((1,4), (8,3), (14,0)))#defining print method that calls add_tuples method takes value in parameters

print(add_tuples((3,2), (11,1), (-2,6)))#defining print method that calls add_tuples method takes value in parameters

Output:

Please find the attached file.

Learn more:

brainly.com/question/17079721

4 0

2 years ago

Write multiple if statements. If car_year is 1969 or earlier, print "Few safety features." If 1970 or later, print "Probably has

Kazeer [188]

Answer:

import java.util.Scanner;

public class Hggg {

public static void main (String [] args) {

System.out.println("Enter the car make year");

Scanner in = new Scanner(System.in);

int car_year = in.nextInt();

if (car_year<1969){

System.out.println("Few safety features.");

}

else if (car_year>=1970 && car_year<1990){

System.out.println("Probably has seat belts.");

}

else if (car_year>=1990 && car_year<2000){

System.out.println("Probably has seat belts.");

System.out.println("Probably has antilock brakes.");

}

else if (car_year>=2000){

System.out.println("Probably has seat belts.");

System.out.println("Probably has antilock brakes.");

System.out.println("Probably has airbags.");

}

Explanation:

In this solution, multiple if statements have been used to accomplish each step. Observe that there are more than one print statements when year is greater than 1990 because the condition applied to year greater than 1970 holds true for every year greater than 1970 (1990, 2000 etc)

3 0

2 years ago

RADIAC instruments that operate on the ionization principle are broken down into three main categories based on what?

mash [69]

Answer:

Electrical potential.

Explanation:

RADIAC Meter or instruments ( also known as radiation monitoring instruments) are measuring instruments that uses the principles of gaseous ionisation to conduct electricity flow internally to deflect the pointer for its Meter readings. These instruments can be analogue or digital.

They are used in industries to monitor the operation of certain equipments and processes. The level of electrical potential flow in the system determines the state or category of the instrument. Out of six, there are three main categories of electrical potential level.

6 0

2 years ago

Ted knows that macros can be helpful to him in his work with Excel spreadsheets,but he also knows they have their hazards,so he

laila [671]

Answer:

Hhhhhhhhjjjffhkvs4hjtth

Explanation:

H*jhfujttjhfhjfhhdtjdgndrjgr7kvykngimg6

3 0

2 years ago

Write a static generic method PairUtil.minmax that computes the minimum and maximum elements of an array of type T and returns a

Gnesinka [82]

Answer:

Explanation:

The following code is written in Java. It is hard to fully create the code without the rest of the needed code including the T class and the Measurable interface. Regardless the following code can be implemented if you have that code available.

public static T minmax(ArrayList<T> mylist) {

T min = new T();

T max = new T();

for (int x = 0; x < mylist.size(); x++) {

if (mylist.get(x) > max) {

max = mylist.get(x);

} else if (mylist.get(x) < min) {

min = mylist.get(x);

}

return (min, max);

}

5 0

2 years ago