Question

Four squares ABCD, EFGH, IJKL, and MNOP are constructed such that points E, F, G, H are middle points (midpoints) of the sides of square ABCD. Points I, J, K, L are midpoints of the square EFGH. M, N, O, and P are midpoints of the square IJKL. What is the area of the square ABCD, if OP=2 cm?

Answer 1

By definition, the area of the parallelogram is given by:

A = b * h

Where,

b: base

h: height

We have then:

ABCD parallelogram:

A = (3) * (3)

A = 9 units ^ 2

EFGH parallelogram:

A = (3) * (3)

A = 9 units ^ 2

Answer:

The area of parallelogram ABCD is equal to the area of parallelogram EFGH.

Answer 2

Answer:

The sum of interior angles of a polygon of n sides is (n-2) straight ... A rhombus is a parallelogram in which adjacent sides are equal.

Step-by-step explanation:

shaded area =0.8cm2. Explanation: enter image source here. Given 3CG=2GF,⇒CG:GF=2:3,⇒CG:CF=2:5 ⇒CG=25CF.