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Sidana [21]
2 years ago
3

To place the first paving stone in a path, Alex starts at the crate of stones, walks three feet, places the stone, and returns t

o the crate. For each subsequent stone, Alex walks two feet farther each way. Alex will place the first 50 stones in a path. After returning to the crate from placing the stone, what is the total distance Alex walked, in feet?
Mathematics
1 answer:
Tamiku [17]2 years ago
6 0

Answer:

The distance covered is 5200 feet.

Step-by-step explanation:

From the starting stone to the last the distance between them is of 2 feet. There are 50 stones and the distance between the crate and first stone is 3 feet.

He walked to the first stone 3 feet and then came back 3 feet and that totals 6 feet. Again he started moving towards the first stone and then the second stone 3+2= 5

The first stone is

2(3) + 2(1) + 2(2) + 2(3)+.......2( 48) +2(49).

The first  term is 6 and the last term is 100 which gives a sum of 6+ 98= 104

Similarly the second term is 8 and the second last is 96  which gives a total of 96+ 8= 104

As there are 50 stones  the total distance would be

104* 50= 5200

As Alex went and came back the distance would be 5200 feet.

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