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2 years ago

Which atom has higher shielding effect Li and Na

Chemistry

1 answer:

love history [14]2 years ago

6 0

Answer:

Na have higher shielding effect than Li

*According to my chemistry bookNa have higher shielding effect than Li

Explanation:

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Estimate the increase in the molar entropy of O2(g) when the temperature is increased at constant pressure from 298 K to 348 K,

Tamiku [17]

Explanation:

It is known that relation between entropy, heat energy and temperature is as follows.

dS = $\frac{Q}{T}$

$\int dS = \int \frac{Q}{T}$

Also we know that at constant pressure, Q = $\Delta H = C_{p} - dT$

$\int_{S_{1}}^{S_{2}} dS = \int_{T_{1}}^{T_{2}} C_{p} \frac{dT}{T}$

$\Delta S = C_{p} \int_{T_{1}}^{T_{2}} \frac{dT}{T}$

As the given data is as follows.

$T_{1}$ = 298 K, $T_{2}$ = 348 K

$C_{p}$ = 29.355 J/K mol

Now, putting the given values into the above formula as follows.

$\Delta S = C_{p} ln {T_{1}}^{T_{2}} \frac{dT}{T}$

= $29.355 [ln (348) - ln (298)]$

= $29.355 [5.85 - 5.69]$

= 4.48 J/k mol

Thus, we can conclude that the increase in the molar entropy of given oxygen gas is 4.48 J/k mol.

6 0

2 years ago

Phosphine, ph3(g), combusts in oxygen gas to form water vapor and solid tetraphosphorus decaoxide. express your answer as a bala

djverab [1.8K]

Tetraphosphorus Decaoxide has a molecular formula of P4O10, all else are known. Therefore the balanced chemical equation would be:

4PH3 + 8O2 --> 6H2O + P4O10

Taking into account the phases:

4PH3(g) + 8O2(g) --> 6H2O(g) + P4O10(s)

6 0

2 years ago

A laboratory utilizes a mixture of 10% dimethyl sulfoxide (DMSO) in the freezing and long-term storage of embryonic stem cells.

Mars2501 [29]

Answer:

The correct answer is "1.0100".

Explanation:

Let the volume of mixture be 100 ml.

then,

The volume of DMSO will be 10 mL as well as that of water will be 90 mL.

DMSO will be:

= $10\times 1.1004$

= $11.004 \ g$

The total mass of mixture will be:

= $90+11.004$

= $101.004 \ g$

Density of mixture will be:

= $\frac{Mass}{Volume}$

= $\frac{101.004}{100}$

= $1.01004 \ g/mL$

hence,

Specific gravity of mixture will be:

= $\frac{Density \ of \ mixture}{Density \ of \ water}$

= $\frac{1.01004}{1}$

= $1.0100$

3 0

2 years ago

A generic gas, x, is placed in a sealed glass jar and decomposes to form gaseous y and solid z. 2x(g)↽−−⇀y(g)+z(s) how are these

Aleksandr [31]

Answer: the equilibrium will be displaced to the right leading an increase on the quantities of y(g) and z(s).

Justification:

According to the rules of equilibrium, based on Le Chatellier's priciple, any change in a system in equilibrium will be tried to be compensated to restablish the equilibrium

The higher the amount, and so the concentration, of X(g), the more will the forward reaction proceed leading to an increase on the concentration of the products y(g) and z (s). Look that that will also be accompanied by a decreasing on the pressure, since 2 molecules of the gas X(g) are converted into 1 molecule of the gas y(g).

3 0

2 years ago

Read 2 more answers

A 0.1064 g sample of a pesticide was decomposed by the action of sodium biphenyl. The liberated Cl- was extracted with water and

Ilya [14]

Answer:

Percentage of an aldrin in the sample is 44.41%.

Explanation:

$Cl^-+AgNO_3\rightarrow AgCl+NO_{3}^-$