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2 years ago

Using approximations to 1 significant figure,

Mathematics

1 answer:

malfutka [58]2 years ago

5 0

Answer:

200

Step-by-step explanation:

Given:

0.482 x 61.2^2 ÷ √98.01

61.2^2 = 3745.44

√98.01 = 9.9

So,

0.482 × 3745.44 ÷ 9.9

= 1,805.30208 ÷ 9.9

= 182.35374545454

To one significant figure

= 200

One significant figure means only 1 non zero value and others are zero

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Triangle cde maps to triangle lmn with the transformation (x,y) —> (x+3,y-2) —> (2/3x, 2/3y)

Mamont248 [21]

The answer is 890 best answer

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2 years ago

If f'(x)=2/x and f(sqrt(e))=5, then f(e)=

docker41 [41]

$f'(x)=\dfrac2x$
$\implies f(x)=\displaystyle\frac2x\,\mathrm dx=2\ln|x|+C$

$f(\sqrt e)=5\implies 5=2\ln|\sqrt e|+C$
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$\implies f(x)=2\ln|x|+4$
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2 years ago

2.14x - 42.9 for x = 22.4 ?<br> A. -18.36<br> B. 5.026<br> C. 47.939<br> D. 90.839

Fynjy0 [20]

Answer:

Step-by-step explanation:

Your answer would be B., because you would multiply

2.14 x 22.4 =

47.939

then you will subtract that by 42.9

47.939 - 42.9 =

5.026

7 0

2 years ago

Nicole bought six pounds of apples at $1.50 per pound. The store had a discount of $2 off her total purchase. Nicole and her fri

Andru [333]

Answer:

Step-by-step explanation:

Total amount of apples that Nicole bought was 6 pounds.

Each pound of apple cost $1.50

This means that the total cost of the 6 pounds of apple that Nicole bought would be

6 × 1.5 = $9

The store had a discount of $2 off her total purchase. This means that the amount that was paid is

9 - 2 = $7

If Nicole and her friend then divided the cost of the purchase evenly, let x represent the amount that each of them would pay. Therefore, the expression that can be used to determine how much Nicole and her friend each paid for the apples would be

x = 7/2

6 0

2 years ago

A theatre has the capacity to seat people across two levels, the Circle and

andriy [413]

Answer: $76.19\%$

Step-by-step explanation:

<h3> The complete exercise is: " A theatre has the capacity to seat people across two levels, the Circle, and the stalls. The ratio of the number of seats in the circle to a number of seats in the stalls is 2:5. Last Friday, the audience occupied all the 528 seats in the circle and $\frac{2}{3}$ of the seats in the stalls. What is the percentage of occupancy of the theatre last Friday?"</h3>

Let be "s" the total number of seats in the Stalls.

The problem says that the ratio of the number of seats in the Circle to the number of seats in the Stalls is $2:5$ .

Since the number of seats that were occupied last Friday was 528 seats, we can set up the following proportion:

$\frac{2}{5}=\frac{528}{s}$

Solving for "s", we get:

$s*\frac{2}{5}=528\\\\s=528*\frac{5}{2}\\\\s=1,320$

So the sum of the number of seats in the Circle and the number of seats in the Stalls, is:

$Total=1,320\ seats+528\ seats=1,848\ seats$

We know that $\frac{2}{3}$ of the seats in the Stalls were occupied. Then, the number of seat in the Stalls that were occupied is:

$(1,320)(\frac{2}{3})=880$

Therefore, the total number of seats that were occupied las Friday is:

$Total\ occupied=880\ seats+528\ seats=1,408\ seats$

Knowing this, we can set up the following proportion, where "p" is the the percentage of occupancy of the theatre last Friday:

$\frac{100}{1,848}=\frac{p}{1,408}$

Solving for "p", we get:

$(1,408)(\frac{100}{1,848})=p\\\\p=76.19\%$

8 0

2 years ago