Answer:
Step-by-step explanation:
Since we are not told what to find, we can as well find the time taken by the rocket to reach its maximum height as shown
The rocket reaches its maximum height when the velocity is zero
v = dh/dt
v = -32t+64
Since v = 0 at maximum height
0 = -32t+64
32t = 64
t = 64/32
t = 2secs
Hence the rocket reaches the maximum height after 2secs
Answer:
9.012 9.1 9.157 9.354
Step-by-step explanation:
Answer:
y2 = (6x + 7)/36 + (Dx + E)e^x
Step-by-step explanation:
The method of reduction of order is applicable for second-order differential equations.
For a known solution y1 of a 2nd order differential equation, this method assumes a second solution in the form Uy1 which satisfies the said differential equation. It then assumes a reduced order for U'' (w' = U'').
The differential equation becomes easy to solve, and all that is left are integration and substitutions.
Check attachments for the solution to this problem.
The first answer is correct, if you go back by 5% each year you will see that.
Answer:
7.56 km²
Step-by-step explanation:
Given data:
Width of the fjord, w = 6.3 km
Retreated terminus of the glacier between may 2001 and June 2005, d = 7.5 km
thus, the length lost , y = 7.5 - 6.3 = 1.2 km
now, the area is given as:
A = Length × width
on substituting the values, we get
A = 1.2 × 6.3
or
A = 7.56 km²
Hence, the surface area lost by the glacier in the fjord is 7.56 km²
