P and q are points on the line 3y

A street promotion worker gets paid $0.10 for each flyer he hands out. His goal is to make $16 an hour. How many flyers must he

Lapatulllka [165]

The answer is 160
hope this helps

3 0

2 years ago

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What is a 6% pay increase to 62,900 annual salary

Pavel [41]

The answer is $66,674.

4 0

2 years ago

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A bakery sells rolls in units of a dozen. The demand X (in 1000 units) for rolls has a gamma distribution with parameters α = 3,

bearhunter [10]

Answer:

The value is $E(X) = \$ 1.7067$

Step-by-step explanation:

From the question we are told that

The parameters are α = 3, θ = 0.5

The cost of making a unit on the first day is c = $2

The selling price of a unit on the first day is s = $5

The selling price of a leftover unit on the second day is v = $ 1

Generally the profit of a unit on the first day is

$p_1 = 5 - 2$

$p_1 = \$3$

The profit of a unit on the second day is

$p_2 = 1 - 2$

=> $p_2 = - \$1$

Generally the probability of making profit greater than $ 1 is mathematically represented as

$P(X > 1 ) = Gamma (X ,\alpha , \theta)$

=> $P(X > 1 ) = Gamma (1 ,3 , 0.5)$

Now from the gamma distribution table we have that

$P(X > 1 ) = 0.67668$

Generally the probability of making profit less than or equal to $ 1 is mathematically represented as

$P(X \le 1 ) = 1 - P(X > 1 )$

=> $P(X \le 1 ) = 1 - 0.67668$

=> $P(X \le 1 ) = 0.32332$

So the probability of making $3 is $P(X > 1 ) = 0.67668$

and the probability of making -$1 is $P(X \le 1 ) = 0.32332$

Generally the value of profit per day is mathematically represented as

$E(X) = 3 * P(X > 1 ) + (-1 * P(X \le 1 ) )$

=> $E(X) = 3 * 0.67668 + (-1 * 0.32332 )$

=> $E(X) = \$ 1.7067$

4 0

2 years ago

Becky created a graph to represent her distance away from home one afternoon. She left home and ran to the park, met some friend

yanalaym [24]

Answer: The first graph is the right graph according to the given situation.

Step-by-step explanation:

Given: Becky created a graph to represent her distance away from home one afternoon.

She left home and ran to the park⇒ She started running from zero distance from the home .⇒the second and fourth graphs are wrong .

After that she met some friends and stayed at the park, then walked back home using the same route.⇒ The first one is correct because there we can see the graph is parallel to time axis for a interval but in the third one it shows that she she hasn't took rest .

6 0

2 years ago

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Kristie has taken five tests in science class. The average of all five of Kristie's test scores is 94. The average of her last t

Bingel [31]

Answer: The average of the first two test scores is 97.

Step-by-step explanation: Given that Kristie has taken five tests in science class. The average of all five of Kristie's test scores is 94 and the average of her last three test scores is 92.

We are to find the average score of her first two tests.

Let a1, a2, a3, a4 and a5 be teh scores of Kristle in first , second, third, fourth and fifth tests respectively.

Then, according to the given information, we have

$\dfrac{a1+a2+a3+a4+a5}{5}=94\\\\\Rightarrow a1+a2+a3+a4+a5=94\times5\\\\\Rightarrow a1+a2+a3+a4+a5=470~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

and

$\dfrac{a3+a4+a5}{3}=92\\\\\Rightarrow a3+a4+a5=92\times3\\\\\Rightarrow a3+a4+a5=276~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

Subtracting equation (ii) from equation (i), we get

$(a1+a2+a3+a4+a5)-(a3+a4+a5)=470-276\\\\\Rightarrow a1+a2=194\\\\\Rightarrow \dfrac{a1+a2}{2}=\dfrac{194}{2}\\\\\Rightarrow \dfrac{a1+a2}{2}=97.$

Thus, the average of the first two test scores is 97.

6 0

2 years ago

P and q are points on the line 3y - 4x = 12