Question

A transportation engineer uses the formula, R = 1600/15+127e, to determine the minimum radius of curvature (R) in meters, for a roadway with a 40 km/hr design speed and a maximum superelevation rate (e). What is the maximum superelevation rate recommended if the radius of curvature is 350 meters? Answer as a decimal, rounded to two decimal places.

Answer 1

Answer:

The value is  $e = 1.92$

Step-by-step explanation:

From the question we are told that

   The formula for radius of curvature is $R = \frac{1600}{15} +127e$

   The design speed of the roadway is  $v = 40 \ km/hr$

    The value of radius of curvature considered R =  350 m

From the equation given e is the superelevation rate

Now making the subject of the formula

        $e = \frac{R}{127} - \frac{1600}{1905}$

At R= 350

         $e = \frac{350 }{127} - \frac{1600}{1905}$

          $e = 1.92$