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Contact [7]
2 years ago
8

A transportation engineer uses the formula, R = 1600/15+127e, to determine the minimum radius of curvature (R) in meters, for a

roadway with a 40 km/hr design speed and a maximum superelevation rate (e). What is the maximum superelevation rate recommended if the radius of curvature is 350 meters? Answer as a decimal, rounded to two decimal places.
Mathematics
1 answer:
Mashcka [7]2 years ago
5 0

Answer:

The value is  e  =  1.92

Step-by-step explanation:

From the question we are told that

   The formula for radius of curvature is R = \frac{1600}{15} +127e

   The design speed of the roadway is  v =  40 \ km/hr

    The value of radius of curvature considered R =  350 m

From the equation given e is the superelevation rate

Now making the subject of the formula

        e  =  \frac{R}{127}  - \frac{1600}{1905}

At R= 350

         e  =  \frac{350 }{127}  - \frac{1600}{1905}

          e  =  1.92

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Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

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