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Pani-rosa [81]
2 years ago
13

Annabelle lives at Bermondsey in London. She has to speak at a conference in Birmingham at 10.30am.

Mathematics
2 answers:
balu736 [363]2 years ago
7 0
If she lives in bermondesy what team do you reckon she supports I reckon she supports Charlton or Millwall

OleMash [197]2 years ago
3 0

Answer:

The conference in Birmingham is at 10.30am.

She has to leave at 08.00 am from her home.

Step-by-step explanation:

Because  

• Time to get Euston Rail Station is 1 hour so she will be at station at 09.00 am.

• Trains to Birmingham run at the following times: 5 minutes past the hour, 25 minutes past the hour and 45 minutes past the hour. Which means she will get the train at 9.05 am.

• The train journey from Euston to Birmingham is an hour and 10 minutes so she will reach Birmingham station at 10.15 am.

• She will reach the meeting venue in Birmingham at 10.20 am as there is a 5-minute walk from the Birmingham station to meeting venue.

She will reach to meeting time 10 minutes earlier which will allow here to get ready for the meeting.

Note:

If we want to overcome the 10 minutes and she live 8.10 am from here home then she will reach to station at 9.10 am. According to the train timing she will get train at 09.25 am which means at the end she will get late about 10 minutes to reach the venue for the meeting.

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sveta [45]

Answer:

-\frac{2}{3}i - \frac{13}{5}j

Step-by-step explanation:

-0.4(3i + 4i) - 0.3(-2i + 5j) + 0.2(-\frac{1}{3}i + \frac{5}{2}j)

-1.2i - 1.6j + 0.6i - 1.5j - \frac{0.2}{3}i + 0.5j

Converting to fraction form;

-\frac{6}{5}i + \frac{3}{5}i - \frac{1}{15}i - \frac{8}{5}j - \frac{3}{2}j + \frac{1}{2} j

<u>Solving the i part;</u>

\frac{-18i + 9i - i}{15} = -\frac{2}{3}i

<u>Solving the j part;</u>

\frac{-16j-15j+5j}{10} = -\frac{13}{5}j

So -0.4a - o.3b + 0.2d =  -\frac{2}{3}i - \frac{13}{5}j

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2 years ago
Natalia has 48 tiles.Write a factor pair for the number 48.
sashaice [31]
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Step-by-step explanation:

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Let us get U first using the formula

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Answer:

A is incorrect!  <u>B. should be the correct answer</u>

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After some research, i found that the correct answer is most likely <u><em>B.  a regression line and trend line are equivalent terms</em></u>

<em />

<em>A trendline and a regression can be the same. </em>

<em> A regression line is based upon the best fitting curve Y= a + bX Most often it’s a least-squares fit (where the squared distances from the points to the line (along the Y-axis) is minimized). </em>

<em> It can be quadratic or logistic or otherwise, but most often it is linear. </em>

<em> A trendline is often constructed by smoothing of the results, making it less peaked. (often by using a moving average); but can also come from ARIMA projections or curve fitting techniques (such as regression).</em>

<em />

Let me know if i helped you!

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