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pashok25 [27]
2 years ago
6

Randy is building a fence at the side of his warehouse. He has 120 m of fencing and plans to use the

Mathematics
1 answer:
skad [1K]2 years ago
8 0

Answer:

The width (side perpedicular to the wall of the werehouse):  <u>x = 30 m</u>

The lenght (side parallel to the wall of the werehouse):  <u>y = 60 m</u>

Step-by-step explanation:

x - the width of the fenced area

Randy has 120 m of fencing so for the lenght remain (120-2x) m of fencing:

y = 120 - 2x

Area of the fencing:  A = x•y

A(x) = x•(120 - 2x)

A(x) = -2x² + 120x              ←  quadratic function

The maximum value of quadratic function occurs at:  x=-\frac b{2a}

a = -2     b = 120

x=-\frac b{2a}=-\frac{120}{2\cdot(-2)}=-\frac{120}{-4}=30

y = 120 - 2•30 = 60

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(3.2+4x)+(18.25+6x)=

Simplifying

(3.2 + 4x) + (18.25 + 6x) = 0

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Remove parenthesis around (18.25 + 6x)

3.2 + 4x + 18.25 + 6x = 0

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