Answer : y=<span>2,904-121x , x for month
when you replace any number in "x" you mean how many months you pay (witch mean the sums of the all (121$) ) so when you </span>Subtract this all 121$ value you will get the the value of what you <span>still owes </span>
Answer:
Yes, it would be statistically significant
Step-by-step explanation:
The information given are;
The percentage of jawbreakers it produces that weigh more than 0.4 ounces = 60%
Number of jawbreakers in the sample, n = 800
The mean proportion of jawbreakers that weigh more than 0.4 = 60% = 0.6 =
=p
The formula for the standard deviation of a proportion is 
Solving for the standard deviation gives;

Given that the mean proportion is 0.6, the expected value of jawbreakers that weigh more than 0.4 in the sample of 800 = 800*0.6 = 480
For statistical significance the difference from the mean = 2×
= 2*0.0173 = 0.0346 the equivalent number of Jaw breakers = 800*0.0346 = 27.7
The z-score of 494 jawbreakers is given as follows;


Therefore, the z-score more than 2 ×
which is significant.
Answer:
See the figure attached
Step-by-step explanation:
Let's call :
x: positive response
y: negative response
then the score is:
2x - 3y
A career placement test eliminates a profession when a person receives a score of 18 or less, that's represented by the following inequality:
2x - 3y ≤ 18
If you have an item that costs 10 dollars and a sales tax of 7% you could do it this way
10 * 7/100 = 0.70 dollars.
The total cost is 10.70 dollars. or 10 dollars and 70 cents.
The best way to do the total however is to multiply the cost by 1.07. You will get the number the customer has to pay.
10 * 1.07 = 10.70
So for any price (p) it would be 1.07*p