Question

A greeting card uses a geometric design containing 4 congruent kites. The card is 4 inches wide and 8 inches long. What is the area of one kite? 4 sq. in. 8 sq. in. 12 sq. in. 16 sq. in.

Answer 1

The correct answer would be option A. 4 sq. inches

Answer 2

Answer:

4 square inches

Step-by-step explanation:

Refer the attached figure .

Since the card is 8 inches long .

So, length of Vertical diagonal of 1 kite + length of Vertical diagonal of another kite = 8

Since we are given that the kites are congruent

So, length of Vertical diagonal of both kites will be same

So, 2 (length of Vertical diagonal of 1 kite ) = 8

So, length of Vertical diagonal of 1 kite = 4 inches

Now width of card is 4 inches

So, length of Horizontal diagonal of 1 kite + length of Horizontal diagonal of another kite =4

Since we are given that the kites are congruent

So, length of Horizontal diagonal of both kites will be same

So, 2 (length of Horizontal diagonal of 1 kite ) = 4

So, length of Horizontal diagonal of 1 kite = 2 inches

So length of vertical diagonal of kite is 4 inches and horizontal diagonal is 2 inches

So, Area of kite = $\frac{pq}{2}$

Where p and q are the diagonals of kite

Area of kite = $\frac{4 \times 2}{2}$

                   = $4 inches^2$

Hence the area of one kite is 4 sq. inches.