Answer:
Therefore, the probability is P=3/32.
Step-by-step explanation:
We know that Hiro has a stack of cards with one number from the set 1, 1, 2, 2, 3, 3, 3, 4 written on each card.
We calculate the probability that he pulls out a 3 first and then pulls out a 2 without replacing them.
The probability that he pulls out a 3 first is 3/8.
The probability of a second card being 2 is 2/8.
We get:
Therefore, the probability is P=3/32.
To factor completely 18b - 32, we factor out the common factor of the two terms and divide each of term by the common factor.
18b - 32 = 2(18b/2 - 32/2) = 2(9b - 16)
Answer:
g(n) = 0.05·2^n
Step-by-step explanation:
The paper with no folds is 0.05 mm thick. Each fold multiplies the thickness by 2, so the function is ...
g(n) = 0.05·2^n
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<em>Comment on paper folding</em>
In practice, where the paper must bend around the fold, it is impossible to fold an ordinary piece of paper 9 times. You may be able to fold a very large, very thin piece of paper that many times.
