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2 years ago

What property describes the number sentence? 6+0=6

Mathematics

2 answers:

yanalaym [24]2 years ago

6 0

Additive property 6+0=6

Afina-wow [57]2 years ago

6 0

Or the additive identity property. That is the full name.

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You and your mom enter a drawing with 3 different prizes. A total of 8 people entered the drawing, and prizes are awarded random

Rashid [163]

It's actually C. 6/336

8 0

2 years ago

Read 2 more answers

Are triangles ADC and EBC congruent? triangle ADC is overlapping triangle EBC so that they both share angle ACE, point B is on s

Olin [163]

Answer:

Yes, by AAS ⇒ 2nd answer

Step-by-step explanation:

* Lets revise the cases of congruence

- SSS ⇒ 3 sides in the 1st Δ ≅ 3 corresponding sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 corresponding

sides and including angle in the 2nd Δ

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ ≅

2 corresponding angles and the side whose joining them in the 2nd Δ

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 corresponding

angles and one side in the 2ndΔ

* Lets solve the problem

- In 2 Δs ADC and EBC

∵ ∠ACE is a common angle in the two triangles ⇒ given

∵ ∠CAD ≅ ∠CEB ⇒ because they marked with the same symbol

∵ DC ≅ BC ⇒ because they marked with the same symbol

- Two angles and one side in Δ ADC ≅ two corresponding angles

and one side in Δ EBC

∴ Triangles ADC and EBC congruent by AAS

* Yes Triangles ADC and EBC congruent by AAS

8 0

2 years ago

Read 2 more answers

An anthropologist finds that a prehistoric bone contains less than 8.1% of the amount of Carbon-14 the bones would have containe

stealth61 [152]

Answer:

20,944 years

Step-by-step explanation:

The formula you use for this type of decay problem is the one that uses the decay constant as opposed to the half life in years. We are given the k value of .00012. If we don't know how much carbon was in the bones when the person was alive, it would be safer to say that when he was alive he had 100% of his carbon. What's left then is 8.1%. Because the 8.1% is left over from 100% after t years, we don't need to worry about converting that percent into a decimal. We can use the 8.1. Here's the formula:

$N(t)=N_{0} e^{-kt}$

where N(t) is the amount left over after the decay occurs, $N_{0}$ is the initial amount, -k is the constant of decay (it's negative cuz decay is a taking away from as opposed to a giving to) and t is the time in years. Filling in accordingly,

$8.1=100e^{-.00012t}$

Begin by dividing the 100 on both sides to get

$.081=e^{-.00012t}$

Now take the natural log of both sides. Since the base of a natual log is e, natural logs and e "undo" each other, much like taking the square root of a squared number.

ln(.081)= -.00012t

Take the natual log of .081 on your calculator to get

-2.513306124 = -.00012t

Now divide both sides by -.00012 to get t = 20,944 years

4 0

2 years ago

Evaluate the expression. P(9, 3) · P(5, 4)

boyakko [2]

Answer:

$P(9,3) *P(5,4)$

And if we use the permutation formula given by:

$nPx = \frac{n!}{(n-x)!}$

And replacing we got:

$\frac{9!}{6!} \frac{5!}{4!}= 504*5 = 2520$

Step-by-step explanation:

For this problem we want to find the following expressionÑ

$P(9,3) *P(5,4)$

And if we use the permutation formula given by:

$nPx = \frac{n!}{(n-x)!}$

And replacing we got:

$\frac{9!}{6!} \frac{5!}{4!}= 504*5 = 2520$

6 0

2 years ago

How do you solve -9( -4r + 6s ) + 3s - 7(6s - 2r)

slavikrds [6]

Answer: 2.1 Pull out like factors :

6s - 2r = -2 • (r - 3s)

Equation at the end of step

((0-(9•(6s-4r)))+3s)--14•(r-3s)

Pulling out like terms

4.1 Pull out like factors : 6s - 4r = -2 • (2r - 3s)

Equation at the end of step

((0--18•(2r-3s))+3s)--14•(r-3s)

Final result :

50r - 93s

7 0

2 years ago