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Butoxors [25]
2 years ago
6

A computer never gets tired or bored while working for a long time .. ​

Computers and Technology
1 answer:
Angelina_Jolie [31]2 years ago
5 0

Answer :Computers never get tired or bored because of doing the same task continuously. They work in the same manner all the time. A computer can store large amount of information in its memory.

Explanation: it is quality which makes the user to be dependent on computer. As we all know, computer systems do repetitive tasks without any boredom, tiredness, or fatigue.

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Given three dictionaries, associated with the variables, canadian_capitals, mexican_capitals, and us_capitals, that map province
Nookie1986 [14]

Answer:

The Python code to combine the three dictionaries are is given as follows:

  1. canadian_capital = {
  2.    cash: "SOME VALUES",
  3.    assets: "SOME VALUES"
  4. }
  5. mexican_capital = {
  6.    cash: "SOME VALUES",
  7.    assets: "SOME VALUES"
  8. }
  9. us_capital = {
  10.    cash: "SOME VALUES",
  11.    assets: "SOME VALUES"
  12. }
  13. nafta_capital = {
  14.    canadian: canadian_capital,
  15.    mexican : mexican_capital,
  16.    us: us_capital
  17. }

Explanation:

<u>Line 1 - 14 :</u>

Create three Python dictionaries and name them as <em>canadian_capitals, mexican_capital </em>and<em> us_capitals</em>. Please note a Python dictionaries should be enclosed in curly braces { }.  

We just define two samples of relevant keys (<em>cash </em>and <em>asset</em>) in each of the dictionaries. Python dictionary can map a key to a value.

Since we are not given any capital values from the question,  a dummy string "<em>SOME VALUES</em>" is tentatively set as the value for each of the keys.

In practice, we should replace those dummy strings with the real values of capital. The values can be a number, a string, a list and even a nested dictionary.

<u>Line 16 - 20 : </u>

Create one more Python dictionary and name it as <em>nafta_capital</em>.

Since our aim is to combine the three previous dictionaries (<em>canadian_capitals, mexican_capital </em>and <em>us_capitals</em>) and associate it with <em>nafta_capital</em>, we can define three different keys (<em>canadian, mexican </em>and <em>us</em>) in our dictionary nafta_capital.

As mentioned, a value associated with a key can be a nested dictionary. Hence, we just map <em>canadian_capitals, mexican_capital </em>and <em>us_capitals</em> as the value of the keys (<em>canadian, mexican </em>and<em> us</em>) in dictionary<em> nafta_capital,</em> respectively,

By doing so, we have managed to combine three target dictionaries (<em>canadian_capitals, mexican_capital </em>and <em>us_capitals</em> ) into a single dictionary, <em>nafta_capital</em>.

4 0
2 years ago
Jane is designing a print brochure for a retail company. She’s having trouble deciding on the page margin. Which best practice w
8090 [49]

I think the answer will be C

7 0
2 years ago
Read 2 more answers
Match each logical function with its description. AND COUNTIF SUMIF IF tests for a certain condition and returns one of two valu
lakkis [162]
1. IF
2. AND
3. COUNTIF
4. SUMIF
4 0
2 years ago
Which of the following is not a characteristic of a good value log entry
Stolb23 [73]
What are we supposed to find? Help us
6 0
1 year ago
Driving is expensive. Write a program with a car's miles/gallon and gas dollars/gallon (both doubles) as input, and output the g
I am Lyosha [343]

Answer:

#program in Python.

#function to calculate driving cost

def driving_cost(d_miles, m_per_gallon, doll_per_gallon):

   #calculate cost and return the value

   return (d_miles / m_per_gallon) * doll_per_gallon

#read the miles per gallon  

m_per_gallon = float(input("Enter car's miles/gallon:"))

#read dollars per gallon

doll_per_gallon = float(input("Enter gas dollars/gallon:"))

#call function to find cost for 10 miles

print('%0.2f' % driving_cost(10, m_per_gallon, doll_per_gallon))

#call function to find cost for 50 miles

print('%0.2f' % driving_cost(50, m_per_gallon, doll_per_gallon))

#call function to find cost for 400 miles

print('%0.2f' % driving_cost(400, m_per_gallon, doll_per_gallon))

Explanation:

Read the value of miles per gallon and assign it to variable "m_per_gallon". Then read dollars per gallon from user and assign it to variable "doll_per_gallon". Call the function driving_cost() with parameter miles, m_per_gallon and doll_per_gallon. This function will find the cost of driving and return the cost.Call function for  10, 50 and 400 miles.

Output:

Enter car's miles/gallon:20                                                                                                

Enter gas dollars/gallon:3.1599                                                                                            

1.58                                                                                                                      

7.90                                                                                                                      

63.20

5 0
2 years ago
Read 2 more answers
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