All categories

2 years ago

Which is true of case-based reasoning (CBR)?

Computers and Technology

1 answer:

DaniilM [7]2 years ago

4 0

Answer:

The correct option is Option C: It matches a new problem with a previously solved problem and its solution.

Explanation:

Case-based reasoning (CBR) is used when someone tries to solve new problems based on old problems that were similar. The person applying case-based reasoning would look for the solutions to these similar past problems and try to apply them to the new case. For example, a doctor who tries to treat a patient based on what was successful with a prior patient with a similar problem is applying case-based reasoning. In some instances, these problems are available in a database and ideally, that is how it is conceived, but it would depend on the field and the kind of problems. There is no universal global network dedicated to CBR as a whole (other than generic searches on the internet in general). One example of a specific CBR database is the European Nuclear Preparedness system called PREPARE.

You might be interested in

Define a structure type auto_t to represent an automobile. Include components for the make and model (strings), the odometer rea

yulyashka [42]

Answer:

see explaination

Explanation:

#include <stdio.h>

#include <string.h>

#define BUFSIZE 1000

struct auto_t scan_auto(char *);

struct date_t {

char day[2];

char month[2];

char year[4];

};

struct tank_t {

char tankCapacity[10];

char currentFuelLevel[10];

};

struct auto_t {

char make[50];

char model[50];

char odometerReading[10];

struct date_t manufactureDate;

struct date_t purchaseDate;

struct tank_t gasTank;

};

int main(int argc, char *argv[]) {

/* the first command-line parameter is in argv[1]

(arg[0] is the name of the program) */

FILE *fp = fopen(argv[1], "r"); /* "r" = open for reading */

char buff[BUFSIZE]; /* a buffer to hold what you read in */

struct auto_t newAuto;

/* read in one line, up to BUFSIZE-1 in length */

while(fgets(buff, BUFSIZE - 1, fp) != NULL)

{

/* buff has one line of the file, do with it what you will... */

newAuto = scan_auto(buff);

printf("%s\n", newAuto.make);

}

fclose(fp); /* close the file */

}

struct auto_t scan_auto(char *line) {

int spacesCount = 0;

int i, endOfMake, endOfModel, endOfOdometer;

for (i = 0; i < sizeof(line); i++) {

if (line[i] == ' ') {

spacesCount++;

if (spacesCount == 1) {

endOfMake = i;

}

else if (spacesCount == 2) {

endOfModel = i;

}

else if (spacesCount == 3) {

endOfOdometer = i;

}

struct auto_t newAuto;

int count = 0;

for (i = 0; i < endOfMake; i++) {

newAuto.make[count++] = line[i];

}

newAuto.make[count] = '\0';

count = 0;

for (i = endOfMake+1; i < endOfModel; i++) {

newAuto.model[count++] = line[i];

}

newAuto.model[count] = '\0';

count = 0;

for (i = endOfModel+1; i < endOfOdometer; i++) {

newAuto.odometerReading[count++] = line[i];

}

newAuto.odometerReading[count] = '\0';

return newAuto;

}

8 0

2 years ago

Write a function called sum_scores. It should take four arguments, where each argument is the team's score for that quarter. It

saw5 [17]

Answer:

Here is the Python program which has a function sum_scores:

def sum_scores(score1, score2, score3, score4):

sum = score1 + score2 + score3 + score4

print(sum)

sum_scores(14,7,3,0)

Explanation:

Method sum_scores takes four arguments, score1, score2, score3, score4.
The sum variable adds these four scores and stores the value of their addition.
Lastly print statement is used to print the value stored in sum variable which is the value obtained by adding the four scores.
Last statement calls the sum_scores method and passes four values to it which are 14,7,3,0
The output of the above program is:
24
If you want to use return statement instead of print statement you can replace print(sum) with return sum. But in order to display the sum of the scores you can replace sum_scores(14,7,3,0) with print(sum_scores(14,7,3,0))
The program along with the output is attached as a screenshot.

5 0

2 years ago

Determine the value of base x if (211)x = (6A)16

elena-14-01-66 [18.8K]

211x=6A•16
211x=96A
211x=96A
___. ___
211. 211

x=96A
___
211

It's hard to show fractions on here :•)

7 0

2 years ago

Read 2 more answers

While in an interactive nslookup session, you'd use the ______ keyword to change the DNS server you're using

serious [3.7K]

Hostname is assigned to a device that would be connected to the computer network and thus would help in identifying the form of electronic communication. While in an interactive nslookup session, one would use the DMNNAMSVR keyword to change the DNS server one is using.

4 0

2 years ago

Read 2 more answers

Assume that a gallon of paint covers about 350 square feet of wall space. Create an application with a main() method that prompt

Makovka662 [10]

Answer:

#include <iostream>

#include <cmath>

using namespace std;

///////////////////////////////////////////////////////////////////////

int noOfGallons(int wallArea) {

int gallon = 350;

int gallon_price = 32.0;

float total_price = 0.0;

///////////////////////////////////////////

float noOfGallons = (float)wallArea/(float)gallon;

printf("No of gallons needed %.2f", noOfGallons);

cout<<endl;

//////////////////////////////////////////

total_price = noOfGallons*gallon_price;

return round(total_price);

}

int wallArea(int length, int width, int height) {

int wall_area = length*width;

int total_price = noOfGallons(wall_area);

}

///////////////////////////////////////////////////////////////////////

int main() {

int length, width, height;

///////////////////////////////////////////

cout<<"Enter length: ";

cin>>length;

cout<<"Enter width: ";

cin>>width;

cout<<"Enter height: ";

cin>>height;

cout<<endl;

///////////////////////////////////////////

int total_price = wallArea(length, width, height);

cout<<"Total price: $"<<total_price;

///////////////////////////////////////////

return 0;

}

5 0

2 years ago