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adell [148]
2 years ago
12

Jace walked a total distance of StartFraction 5 Over 6 EndFraction of a mile to school this week. If he walked the same distance

each of the 5 days, how far did he walk each day?
Mathematics
2 answers:
xxMikexx [17]2 years ago
8 0

He walks 5/6 of a mile each day.

Multiply the distance each day by the number of days:

5/6 x 5

When multiplying a fraction by a whole number, multiply the numerator ( top number) by the whole number and leave the denominator ( bottom number as is)

5/6 x 5 = (5 x5)/6 = 25/6 now rewrite as a proper fraction:

25/6 = 4 1/6 total miles.

vesna_86 [32]2 years ago
7 0

Answer:

4 1/6 miles over the course of 5 days

Step-by-step explanation:

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In a day, Robin spends 6 hours at school, sleeps for 9 hours, plays for 3 hours, and spends the rest of the time doing other thi
slavikrds [6]
6hrs = school
9hrs = sleeps              = 18hrs // 24hrs      ----6hrs left
3hrs = plays

6hrs = other things


playing = 12.5% -- 3/24                 3/24*100
other things = 25% -- 6/24             6/24*100
5 0
2 years ago
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Jarvis works in a garage £6 an hour. If he works on Saturday, he is paid time and a quarter. If he works on Sunday, he is paid t
ruslelena [56]

Answer: He is paid $90 last weekend.

Step-by-step explanation:

Since we have given that

Amount he earns per hour = $6

If he works on Saturday, he is paid time and a quarter .

Amount would be

6\times 1.25=\$7.5

If he works on Sunday, he is paid time and a half.

Amount would be

6\times 1.5=\$9

Number of hours he worked on Saturday = 6 hours

Number of hours he worked on Sunday = 5 hours

So, Total amount he is paid last weekend altogether is given by

6\times 7.5+5\times 9\\\\=\$90

Hence, he is paid $90 last weekend.

4 0
2 years ago
A consensus forecast is the average of a large number of individual analysts' forecasts. Suppose the individual forecasts for a
stealth61 [152]

Answer:

a) 0.954

b) 0.937

c) 0.891  

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  6 percent

Standard Deviation, σ = 1.3 percent

We are given that the distribution of particular interest rate is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(At least 3.8 percent.)

P(x \geq 3.8)

P( x \geq 3.8) = P( z \geq \displaystyle\frac{3.8 - 6}{1.3}) = P(z > -1.69)

= 1 - P(z < -1.69)

Calculation the value from standard normal z table, we have,  

P(x \geq 3.8) = 1 - 0.046 = 0.954 = 95.4\%

b) P(At most 8 percent)

P(x \leq 8) = P(z \leq \displaystyle\frac{8-6}{1.3}) = P(z \leq 1.53)

Calculating the value from the standard normal table we have,

P( x \leq 8) =0.937= 93.7\%

c) P(Between 3.8 percent and 8 percent. )

P(3.8 \leq x \leq 8) = P(-1.69 \leq z \leq 1.53)\\\\= P(z \leq 1.53) - P(z < -1.69)\\= 0.937 - 0.046 = 0.891 = 89.1\%

P(3.8 \leq x \leq 8) = 89.1\%

3 0
2 years ago
Black and Decker Manufacturing sold a set of saws to True Value Hardware. The list price was $3800. Black and Decker offered a c
dangina [55]
Net price
=3,800×(1−0.08)×(1−0.03)×(1−0.01)
=3,357.2088
3 0
2 years ago
6.5% of people in the U.S. Have A- blood type. You randomly select 6 Americans and ask them if their blood type is A-. a) Find t
Keith_Richards [23]

Answer:

a) 7.54189*10^-8

b) 0.99999999

c) E ( X ) = 0.39 , s ( X ) = 0.604

Step-by-step explanation:

Solution:-

- We will assume the proportion of people with A- blood group is independent and remains constant for a fairly small sample of n = 6 Americans selected at random.

- We will denote a random variable X = The number of americans out of 6 that have blood group type A-.

- The random variable is assumed to follow binomial distribution.

- The probability of success is the proportion of people in U.S that have blood group type A-, p = 0.065:

                        X ~ Bin ( 6 , 0.065 )

Where, r represents the number of americans out of selected 6 have blood group A-. The pmf of a binomial variate is given as:

                       P ( X = r ) = nCr * ( p ) ^r * ( 1 - p ) ^ ( n - r )

a) Find the probability that all 6 are type A-

- We will pmf given above and set r = 6. And evaluate the resulting probability:

                     P ( X = 6 ) = 6C6 * ( p )^6 * ( 1  - p ) ^ ( 0 )

                                      = p^6

                                      = ( 0.065 )^6  

                                      = 7.54189*10^-8

b) Find the probability that at most 4 of them are type A-

- We will pmf given above and evaluate the following expression:

                     P ( X ≤ 4 ) = 1 - P ( X = 5 ) - P ( X = 6 )

                     P ( X ≤ 4 ) = 1 - 6C5 * ( p )^5 * ( 1  - p ) ^ ( 1 ) - p^6

                                      = 1 - 6*(0.065)^5 ( 0.935 ) - 0.065^6

                                      = 1 - 6.50923*10^-8 - 7.54189*10^-8        

                                      = 0.99999999          

c) Find the mean and standard deviation.

- The mean E ( X ) of the defined random variable distributed binomially is given by:

                     E ( X ) = n*p = 6*0.065 = 0.39 people

- The mean s( X ) of the defined random variable distributed binomially is given by:

   

                    s ( X ) = √n*p*q = √(6*0.065*0.935) = 0.604

5 0
2 years ago
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