Answer:
Replace /* Your code goes here */ with
for(i =0; i<NUM_VALS; i++)
{
printf("%d", origList[i]*offsetAmount[i]);
printf(";");
}
Explanation:
The first line is an iteration statement iterates from 0 till the last element in origList and offsetAmount
for(i =0; i<NUM_VALS; i++)
{
This line calculates and print the product of element in origList and its corresponding element in offsetAmount
printf("%d", origList[i]*offsetAmount[i]);
This line prints a semicolon after the product has been calculated and printed
printf(";");
Iteration ends here
}
Answer:
CPI = 0.94
Explanation:
The formula for execution time is given below:
Execution time = clock cycles * cycle time
As Execution time = 750 s
clock cycle time = 0.333 ns = 0.333 * 10^-9
so putting these values in the above formula, we get
750 = clock cycles * ( 0.333 * 10^-9 )
clock cycles = 750 / ( 0.333 * 10^-9 )
clock cycles = 2.25 * 10^12
As the results of the spec cpu2006 bzip2 benchmark running on an amd barcelona has an instruction count = 2.389 * 10^12
and the formula for clock cycles is:
clock cycles = number of instructions * CPI
CPI = clock cycles / number of instructions
CPI = 2.25 * 10^12 / 2.389 * 10^12
CPI = 0.94
I should be skeptical of the credibility of sources that I have during the gathering. Be cautious and make sure that data comes of from trusted specialized sources. Trusted sources can be easily identified for their popularity on certain fields. Determine the purpose of the site and the data it contains.
Answer:
Given that:
A= 40n^2
B = 2n^3
By given scenario:
40n^2=2n^3
dividing both sides by 2
20n^2=n^3
dividing both sides by n^2 we get
20 = n
Now putting n=20 in algorithms A and B:
A=40n^2
= 40 (20)^2
= 40 * (400)
A= 16000
B= 2n^3
= 2 (20)^3
= 2(8000)
B= 16000
Now as A and B got same on n = 20, then as given:
n0 <20 for n =20
Let us take n0 = 19, it will prove A is better than B.
We can also match the respective graphs of algorithms of A and B to see which one leads and which one lags, before they cross at n= 20.
Answer:
public class PostAccount
{
public void withdraw(float savings)
{
if (savings >=0 )
{
IllegalArgumentException exception
= new IllegalArgumentException("Savings cannot be negative");
throw exception;
}
balance = savings - withdraw;
}
}
Explanation:
IllgalArgumentException is a type of NumberFormatException of runtime exception. Here in the program we have created an object of IllgalArgumentException class and after that we have thrown the error to show the condition if it does not satisfy the if condition.
