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Anon25 [30]
2 years ago
5

Laura is a chemist working with liquids and solutions. She has two large cylindrical barrels that can hold up to 2,000 liters ea

ch. The first barrel contains 900 liters of solution, and the second barrel contains 100 liters of solution. Laura begins draining the first barrel at a rate of 36 liters per minute at the same time she begins filling the second barrel. Laura fills the second barrel with 44 liters of solution every minute. Which inequality represents the seconds, s, when the second barrel contains a greater or equal amount of solution than the first barrel?
Mathematics
1 answer:
EleoNora [17]2 years ago
6 0

Answer:

900 - 0.6s ≤ 100 + 0.73s

Step-by-step explanation:

The left side is the equation for the first barrel containing 900L and draining at 36L/minute. This means that it drains 0.6L/second.

The right side of the equation is for the second barrel containing 100L and filling at 44L/minute. This means that it fills at 0.73L/second.

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PLEASE HELP I WILL GIVE BRAINLIEST Complete the frequency table: Method of Travel to School Walk/Bike Bus Car Row totals Under a
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11%

Step-by-step explanation:

1. Fill out the table with the correct numbers.

2. After you fillout the numbers, you should notice that under the column car and in the first row, there should be the number 18.

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4. To find the percent:

       18/165 * 100

               = 11%

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The amount of time it takes for a student to complete a statistics quiz is uniformly distributed (or, given by a random variable
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Answer:

(A) 0.15625

(B) 0.1875

(C) Can't be computed

Step-by-step explanation:

We are given that the amount of time it takes for a student to complete a statistics quiz is uniformly distributed between 32 and 64 minutes.

Let X = Amount of time taken by student to complete a statistics quiz

So,   X ~ U(32 , 64)

The PDF of uniform distribution is given by;

    f(X) = \frac{1}{b-a} ,  a < X < b      where a = 32 and b = 64

The CDF of Uniform distribution is P(X <= x) = \frac{x-a}{b-a}

(A) Probability that student requires more than 59 minutes to complete the quiz = P(X > 59)

   P(X > 59) = 1 - P(X <= 59) = 1 - \frac{x-a}{b-a} = 1 - \frac{59-32}{64-32} = 1-\frac{27}{32} = 0.15625

(B) Probability that student completes the quiz in a time between 37 and 43 minutes = P(37 <= X <= 43)  = P(X <= 43) - P(X < 37)

    P(X <= 43) = \frac{43-32}{64-32} = \frac{11}{32} = 0.34375

    P(X < 37) = \frac{37-32}{64-32} = \frac{5}{32} = 0.15625

    P(37 <= X <= 43) = 0.34375 - 0.15625 = 0.1875

(C) Probability that student complete the quiz in exactly 44.74 minutes

     = P(X = 44.74)

The above probability can't be computed because this is a continuous distribution and it can't give point wise probability.

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2 years ago
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