Consider the attached figure. All the triangles shown are similar, so
CB/CA = CD/CB
30/50 = projection/30
projection = 30^2/50
projection = 18
For a hyperbola

where

the directrix is the line

and the focus is at (0, c).
Here, we have c = 5, a² = 9, so b² = 5² - 9 = 16.
a = √9 = 3
b = √16 = 4
Your hyperbola's constants are ...
a = 3
b = 4
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Please note that the equation of a hyperbola has a negative sign for one of the terms. The equation given in your problem statement is that of an ellipse.
Step-by-step explanation:
If the zeros are 5 and 9, then the equation will have the form:
y = a (x–5) (x–9)
We know the point (0, 90) is on the curve, so we can use this to find the coefficient a:
90 = a (0–5) (0–9)
90 = 45a
a = 2
y = 2 (x – 5) (x – 9)
The answer for x^2-6x-16 is (x-8) (x+2) or x = -2