Answer:
Following are the program in python language:
def list_concat(ls): #define function
if(len(ls) == 0): #set if condition
return ""
res = ""
for x in ls: #set for loop
res += x + " "
return res[:len(res)-1] #removing the extra spaces from list
ls = ['limit','break','ready'] #initialize the value in list
print(list_concat(ls)) #call the function
Output:
limit break ready
Explanation:
Here we declared a function "list_concat()" in which we pass an argument "ls" then check if condition that check the length of list .We also Iterating the loop in that function res[:len(res)-1] statement removes the extra space from the list and finally print the list
How efficient well if we are transmitting 6bits and we need 10 to transmit the 6 bits that would be 6/10 = .6 = 60% efficient.
Well knowing how the government is with security id go with A. as it makes a lot of sense unlike B and D and if they were looking for software the question would mention it
Answer:
The purpose of information management is to: design, develop, manage, and use information with insight and innovation. support decision making and create value for individuals, organizations, communities, and societies.
Explanation:
Answer:
def find_max(num_1, num_2):
max_val = 0.0
if (num_1 > num_2): # if num1 is greater than num2,
max_val = num_1 # then num1 is the maxVal.
else: # Otherwise,
max_val = num_2 # num2 is the maxVal
return max_val
max_sum = 0.0
num_a = float(input())
num_b = float(input())
num_y = float(input())
num_z = float(input())
max_sum = find_max(num_a, num_b) + find_max(num_y, num_z)
print('max_sum is:', max_sum)
Explanation:
I added the missing part. Also, you forgot the put parentheses. I highlighted all.
To find the max_sum, you need to call the find_max twice and sum the result of these. In the first call, use the parameters num_a and num_b (This will give you greater among them). In the second call, use the parameters num_y and num_z (This will again give you greater among them)
