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vladimir1956 [14]
1 year ago
15

It can be seen on a cladogram that modern birds and reptiles share a common ancestor. Select the piece of evidence that best sup

ports this idea.
Biology
2 answers:
Sunny_sXe [5.5K]1 year ago
7 0

Answer:

       The right piece of evidence that best supports this idea is: Feathers

Explanation:

       The feathers can be a very good factor to compare both cladograms, once these feather can easily be found in primitive reptiles. Once we find a common characteristic, it's time to analyze the evidence by comparing both cladograms and see where these species, the birds and the reptiles, had a common ancestor, and if that's possible, other characteristics can be analyzed easily.

IRISSAK [1]1 year ago
3 0
It can be seen on a cladogram that modern birds and reptiles share a common ancestor. The piece of evidence that best supports this idea is <span>Feathers are a derived characteristic that first evolved in reptiles.
Both today's birds and ancient reptiles had feathers.</span><span>
</span>
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identify the missing numbers below to show the result of multiplying the numbers. (3.5 × 1016)(2.2 × 1010) = a × 10b
11Alexandr11 [23.1K]
<span>In order to find the value of "a" and "b", first of all perform the multiplication in the parenthesis. 
Thus

(3.5x1016) = 3556
and 
(2.2x1010) = 2222

As per question;
(3556)x(2222) = 10 axb
By dividing both sides by "10"
we get
(3556)x(222.2) = axb
or 
(355.6)x(2222) = axb
by comparing both sides of the equation, 
we get that a = 3556  and b = 222.2
or
a = 355.6 and b = 2222
</span>
4 0
2 years ago
Read 2 more answers
Over 90% of all parasympathetic fibers are derived from cranial nerves ________. v (trigeminal) vii (facial) x (vagus) xii (hypo
Natasha2012 [34]
Over 90% of all parasympathetic fibers are derived from the cranial nerve X, which is the vagus nerve. 
The vagus nerve influences most organs below the neck. The activation of this nerve affects heart rate, blood pressure, production of stomach acid, movement of food through the intestines and breathing. 
8 0
1 year ago
Black fur (B) is dominant to white fur (b) in guinea pigs. An F1 cross was conducted and resulted in 100% heterozygous guinea pi
Lemur [1.5K]

Answer:

D. 1 BB : 2 Bb : 1 bb

Explanation:

This question involves a single gene coding for fur color in guinea pig. Black fur (B) is dominant over white fur (b). This means that, as stated in the question, if a black fur parent (BB) is crossed with a white fur parent (bb), a 100% heterozygous offspring (Bb) with black fur will result.

If two heterozygous guinea pigs are crossed i.e. Bb × Bb, the following gametes will be produced by each heterozygous parent:

Bb = B and b

Using these gametes in a punnet square (see attached image), offsprings with the following genotypic ratio will be produced:

1 BB : 2 Bb : 1 bb

BB and Bb = black fur guinea pigs

bb = white fur guinea pigs

3 0
1 year ago
Suppose a human blood cell containing a 0.9 percent solute concentration were put into a container of 0 percent solute solution
Vladimir [108]

Answer and explanation:

If a human blood cell with a 0.9% solute concentration were to be put into a container of 0% solute solution, the cell would get BIGGER.

<u>The cell contains a </u><u>more concentrated solution</u><u> than the solution in the container</u>. The difference in concentration would produce an <em>osmotic gradient</em> that would cause water from the container to get inside the cell to even the concentrations - this is going to make the cell much bigger because the entering water would bloat the cell.

In this example, the solution in the container is hypotonic in relation to the cell, while the solution inside the cell is hypertonic in relation to the solution in the container. This is why the water will be moving from outside of the cell to the inside of the cell.

6 0
1 year ago
In Kerr and Wright's experiment with 96 fruit-fly populations, only 4 males and 4 females bred in each generation. After 16 gene
Svetradugi [14.3K]

Answer:

2.Less than 73% of the populations would have only one allele present.

Explanation:

The two alleles chosen do not affect the fitness of flies in the lab environment, so Kerr and Wright could be confident that if changes in the frequency of normal and forked phenotypes occurred, they would not be due to natural selection.

Using a larger breeding population would not be expected to alter the outcome of the experiment.

3 0
1 year ago
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