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2 years ago

Starting with a fertilized egg (zygote), a series of five mitotic divisions would produce an early embryo with how many cells?

Biology

1 answer:

pychu [463]2 years ago

8 0

Answer:

32 cells

Explanation:

In each mitotic division, from one cell you are going to have at the end 2 cells. That means that to calculate the number of cells you need to use the formula 2n so 2 at the 5th power will it be 32. In the embriotic process this is called morula by the number of cells.

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Answer:

geographical, environment, determines, growth

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2 years ago

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Enolase is an enzyme that catalyzes one reaction in glycolysis in all organisms that carry out this process. The amino acid sequ

lorasvet [3.4K]

Answer:

a) The response indicates that a pH below or above this range will most likely cause enolase to denature/change its shape and be less efficient or unable to catalyze the reaction.

b)The response indicates that the appropriate negative control is to measure the reaction rate (at the varying substrate concentrations) without any enzyme present.

c)The response indicated that the enolase has a more stable/functional/correct/normal protein structure at the higher temperature of 55°C than at 37°C because the enzyme is from an organism that is adapted to growth at 55°C.

Explanation:

Enolase catalyzes the conversion of 2-phosphoglycerate to phosphoenolpyruvate during both glycolysis and gluconeogenesis.In bacteria, enolases are highly conserved enzymes and commonly exist as homodimers.

The temperature optimum for enolase catalysis was 80°C, close to the measured thermal stability of the protein which was determined to be 75°C, while the pH optimum for enzyme activity was 6.5. The specific activities of purified enolase determined at 25 and 80°C were 147 and 300 U mg−1 of protein, respectively. Km values for the 2-phosphoglycerate/phosphoenolpyruvate reaction determined at 25 and 80°C were 0.16 and 0.03 mM, respectively. The Km values for Mg2+ binding at these temperatures were 2.5 and 1.9 mM, respectively.

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2 years ago

In the diagram below, letter A represent the starting volume of liquid in a graduated cylinder. letter B represents the volume a

ahrayia [7]

The correct answer would be A.
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2 years ago

Primary spermatocytes are diploid (2n) cells with all of the organelles typically found in eukaryotic animal cells. Spermatogene

Aneli [31]

Answer: a. Genetic recombination (crossing over)

b. Can also be explained in terms of crossing over

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Explanation:

The process that allows for the transfer of both the paternal and maternal materials to is the crossing over process that takes at meiosis 1 changing them to secondary spermatocytes. While they are still primary spermatocytes, they are still diploid cells having both the maternal and paternal chromosomes. But since the spermatozoon is an haploid cell, it is able to retail some of both parents chromosome by the crossing over event which takes place between homologous paternal and maternal chromosomes allowing them to exchange materials. Thus the chromosomal contents of the primary spermatocyte differs from that of the spermatozoon.

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