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2 years ago

14

Ellen has five different chores to be done. She assigns all five chores to her four kids. Each kid will have at least one chore.

How many ways can Ellen assign the chores?

1 answer:

Liula [17]2 years ago

5 0

Answer:

by giving one of the four kids 2 chores or stop being lazy and do a chore herself

Step-by-step explanation:

k=kids

c=chores

5c-5k=1c

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A population of 900 voters contains 369 Republicans, 468 Democrats, and 63 independents and members of other parties. A simple r

UkoKoshka [18]

Answer:

Step-by-step explanation:

Total voters = 900

Republicians =369

Democrats =468

Independents = 63

Sample size n =90

a) The expected value of the number of Republicans in the sample is

= $\frac{90*369}{900} =36.90$

b) The chance the sample contains only Republicans and Democrats is

= (no of republicians+democrats)/total people

= $\frac{369+468}{900} =0.93$

c)

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2 years ago

A grasshopper jumps off a tree stump. The height, in feet, of the grasshopper above the ground after t seconds is modeled by the

Monica [59]

The height, in feet, of the grasshopper above the ground after t seconds is modeled by the function , which is

$h(t) =-t^2+\frac{4}{3}t+ \frac{1}{4}$

When the grasshopper land on the ground,

$h(t)=0$

that is,

$-t^2+\frac{4}{3}t+ \frac{1}{4}=0$

Multiplying whole equation by 12 to get rid of denominators 3 and 4

$-12t^2+16t +3=0$

$(3-2t)(6t+1)=0 \\ 3-2t=0 , 6t+1=0 \\ t= \frac{3}{2} , \frac{-1}{6}$

And time cant be negative, so the correct option is

$t = \frac{3}{2}=1.5 seconds$

Correct option is C .

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2 years ago

A lightbulb manufacturer ships large consignments of lightbulbs to big industrial users. When the production process is function

Mashutka [201]

Answer:

a) P[ Pf | Ptd ] = 0,428

b) P[ Pf | Nd ] = 0,692

Step-by-step explanation:

We will call:

Pf Probability of functioning correctly 60 % or 0.6

Pfn Probability of malfunctioning 40 % or 0,4

PNd Probability of nondefective bulb

D₁ Probability of defective bulb when the process is correctly working

D₂ Probability of defective bulb when the process is in malfunction condition

Ptd Total probability of defective bulbs

Then applying theorem´s Bayes have

P [ A | B ] = P(A) * P [ B | A ] / P(B)

a) Probabilty of the process is functioning correctly given that we pick up a defective bulb

The total probability of defective bulbs is equal to, probabilty of defective bulbs when the process is Ok, plus probability of defective bulbs when the process is in malfunctioning condition, therefore

Ptd = (0,6)*(0,25) + (0,40)*(0,50) = 0,15 * 0,20 = 0,35

P[ Pf | Ptd ] = Pf * P [ Pd | Pf ] / Ptd = 0,6 * 0,25 / 0,35

P[ Pf | Ptd ] = 0,428

b) P [ Pf | Nd ]

P[ Pf | Nd ] = Pf * P [Nd | Pf ] / PNd

PNd = 1 - Ptd = 1 - 0,35 = 0,65

P[ Pf | Nd ] = 0,6 * 0,75 / 0,65 = 0,692

P[ Pf | Nd ] = 0,692

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2 years ago

A theater group made appearances in two cities. The hotel charge before tax in the second city was $1000 lower than in the first

Bess [88]

Answer:

$5000 in the first city
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Step-by-step explanation:

Let x represent the pre-tax hotel charge in the first city in dollars. Then the hotel charge in the second city is x-1000 dollars, and the total tax is ...

... 7.5%·x +5%·(x -1000) = 575

... 12.5%·x = 625 . . . . simplify, add 50

... x = 5000 . . . . . . . . divide by 12.5% (=0.125)

The first-city charge was $5000; the second-city charge was $4000.

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2 years ago

A student rolled two six-sided dice 100 times. The table captures the total of the dice on each roll. How to show results using

ivann1987 [24]

I think the best way to show the results in a chart format is to put zero to twelve on the y-axis or vertically and zero to one hundred on the x-axis or horizontally. Label the y-axis total per roll and the x-axis roll number.Then plot the coordinates or pairs from the table.

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2 years ago

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