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Ksenya-84 [330]
2 years ago
11

Two bowlers bruce and donald want to find out who has the higher three-game series when compared to each of their leagues. Bruce

has a score of 500, and his league has a mean score of 620 and a standard deviation of 20. Donald has a score of 520, and his league has a mean of 625 and a standard deviation of 25. Who has the higher three-game series score when compared to each of their leagues?
A. Bruce.


B. Donald.


C. The scores are equal when compared to each of their leagues.
Mathematics
1 answer:
attashe74 [19]2 years ago
7 0

Answer:

Donald

Step-by-step explanation:

Given that :

BRUCE :

score (x) = 500

League average (m) = 620

Standard deviation (σ) = 20

DONALD:

score (x) = 520

League average (m) = 625

Standard deviation (σ) = 25

Take standardized score of both Bruce and Donald

BRUCE:

Zscore = (x - m) / σ

Zscore = (500 - 620) / 20

Zscore = - 120 / 20

Zscore = - 6

DONALD:

Zscore = (x - m) / σ

Zscore = (520 - 625) / 25

Zscore = - 105 / 25

Zscore = - 4.2

Bruce's standardized score is lesser Than Donald's. Hence,

Donald has a higher three-game series score ;

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Answer:

P(made 2nd attempt|made 1st attempt)=P(made 2nd attempt)

Step-by-step explanation:

Here given that a basketball player that shoots 80% from the free throw line attempts two free throws.

If x is the no of shoots he makes (say) then we find that each throw is independent of the other.

In other words, because he made successful first attempt, his chances for second attempt will not change

Prob for success in each attempt remains the same as 0.80

Hence I throw is independent of II throw.

When A and B are independent,then we have

P(A/B) = P(A)

Hence answer is

P(made 2nd attempt|made 1st attempt)=P(made 2nd attempt)


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2 years ago
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6 0
2 years ago
If the two adjacent angles are supplementary then their outer sides are???​
Ainat [17]

Answer:

If the bisectors of two adjacent angles are perpendicular to each other, are the angles then supplementary angles?

Suppose two angles ABC and CBD are x and y.

x+y = 180 deg.

The bisector of angle ABC (BE) and the bisector of angle CBD (CF) will form angle EBF = (x/2)+(y/2) = 180/2 = 90 deg.

Conclusion: If the angle bisectors of two adjacent angles are perpendicular to eaxh other, the adjacent angles are supplementary angle

Adjacent angles are when the 2 angles have a common vertex and a common arm.

if the exterior sides of 2 adjacent angles are perpendicular, then the angles are complementary angles.

Then the sum of the 2 adjacent angles is a right angle - 90°.

When 2 angles add up to 90°, they are called a pair of complementary angles.

Step-by-step explanation:

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1 year ago
K is the midpoint of segment HL . H has coordinates (1, -7 ) , and K has coordinates(-9, 3 ). Find the coordinates of other end
Andrei [34K]

Answer:

Coordinates of other end point L = ( -19, 13 )

Explanation:

 The mid point of the coordinates (a,b) and (c,d) is given by (\frac{a+c}{2},\frac{b+d}{2})

 Here we have (a,b) = (1,-7) and (\frac{a+c}{2},\frac{b+d}{2}) = (-9,3) , we need to find (c,d).

 \frac{a+c}{2} =-9\\ \\ 1+c=-18\\ \\ c=-19\\\\ \frac{b+d}{2} =3\\ \\ -7+d=6\\ \\ d=13

So coordinates of other end point L = ( -19, 13 )

8 0
2 years ago
Read 2 more answers
Luis has saved $6. he doubles the amount he saves each week.does this represent an exponential function?complete:
Ilya [14]

Answer:

This 6(2)^{n-1} represent an exponential function, because his savings increase by a constant factor of 2.

Step-by-step explanation:

It is given that,

Luis has saved $6 and he doubles the amount each week.

So, the amount saved in the next week = 6×2 = 12

This gives the amount saved in the third week = 12×2 = 24

So, we get the sequence 6, 12, 24, 48,.....

It can be written as, 6×2⁰, 6×2¹, 6×2², 6×2³,.....

So, the sequence in the exponential form 6(2)^{n-1}, where 'n' is a natural number.

Also, 6, 12, 24, 48,.....

The numbers are increasing by the factor = \frac{12}{6}=\frac{24}{12}=....=2

Hence, we get,

This 6(2)^{n-1} represent an exponential function, because his savings increase by a constant factor of 2.

8 0
2 years ago
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