Answer:
Distinct mechanisms are used by bacteria in order to transfer the gene from one bacteria to another. These are transformation, transduction, and conjugation. Transformation refers to the process of uptaking extracellular DNA by the recipient of the other bacterial cell.
In the process of transduction, the donor DNA gets packed within the bacteriophage and infects the recipient bacteria. In the process of conjugation, the genetic substance is transferred by the donor bacteria to the recipient via the process of mating.
a. Of all these three mechanisms, transformation is the process that exhibits a broad range and can be easily performed in the lab. As in the process, there is a slight chance of rejection or failure due to direct compatibility between the bacteria.
b. While the narrowest broad range is found in the process of conjugation, as in order to transfer the genetic substance between the two bacterial species, there should be a similarity between the two species so that they can mate and exchange the genetic substance in between them.
Answer:
The normal role of this control element can be that of a negative modulator or regulator
Explanation:
For example, the lactose operon in the bacteria <em>Escherichia coli</em> is negatively regulated. In lactose absence a represor protein is produced, which inserts in the DNA operator site blocking transcription of structural genes. if for example a mutation affects the synthesis of this repressor, expression of structural genes will increase with no regulation.
A mutation in the DNA operator site that avoids insertion of the repressor, too.
A mutation in the gene that codes for the repressor, will also do the job
Answer: True
Explanation:Carbon dioxide is transported is transfer in 3 basic ways to human cells.
About 20 % of C0 2 is transported as Carbaminohemoglobin to reach the lungs carbon dioxide binds directly to the amino acid moieties on the globin portions of the haemoglobin to form carbaminohemoglobin. This is a reversible reaction as shown below.
CO2 + Hb ↔ HbCO2.
The reversible binding of C02 to the haemoglobin is due to the the partial pressure of carbondioxde. In the lungs the partial pressure of C02 is low. Therefore C02 is unbounded from the HB and leaves in the lungs, thus the blood leaving the lungs for the body tissues has low partial pressure C02. Compare to the blood in the tissues with high partial pressure of C02 from metabolic activities of cellular respiration. The C02 therefore diffuses from the tissues to bind with HB to form Carbaminoheamologbin.
In addition C02 is transported by other means.
1. As bicarbonate 70% of the Co2 in the blood is transported and bicarbonate buffer.
CO2 + H2O CA ↔ H2CO3↔H+ + HCO3
2, As soluble carbon dioxide which dissolves directly in to the blood stream; this is about 7-10%
Below are the choices that can be found elsewhere:
a.66 s
<span>b.68 s </span>
<span>c.70 s </span>
<span>d.78 s
</span>
<span>An outlier is a result that is abnormally too high or too low. Most of the results fall between 66 and 70, but 78 seems to be abnormal, so it's your outlier. The answer is D. Hope it helps :)</span>
Answer;
-Keratinized stratified squamous epithelium forms the epidermis of the skin.
-In keratinized stratified squamous epithelial tissue, the cells on the apical (outer) surface are dead.
Explanation;
-Stratified squamous epithelium is a type of tissue found covering and lining parts of the body. Stratified squamous epithelium may be keratinized or nonkeratinized. Non-keratinized surfaces must be kept moist by bodily secretions to prevent them from drying out.
-The cells on the surface of stratified squamous keratinized epithelium are very flat. Not only are they flat, but they are no longer alive. They have no nucleus or organelles. They are filled with a protein called keratin, which is what makes our skin waterproof.
