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DerKrebs [107]
2 years ago
13

Parents wish to have $80,000 available for a child's education. If the child is now 5 years old, how much money must be set asid

e at 6% compounded semiannually to meet their financial goal when the child is 18?
Mathematics
1 answer:
Ludmilka [50]2 years ago
5 0

Answer: $27,602.60

Step-by-step explanation:

if the kid is 5 years old, there are 13 years left until he is 18.

Now, suppose that the parents set aside an amount A of money in the account.

As the interest is compounded semiannually is compounded two times per year.

The equation that models this situation is:

M(n) = A*(1 + p/(c*100%))^(c*n)

where:

n is our variable, in this case, years.

p is the percentage, in this case, 6%

n is the number of compounds in one unit of the variable, in this case, we have 2.

A is the initial amount, this is the thing we want to find.

Then our equation will be:

M(n) = A*(1 + 6%/(2*%100))^(2*n)

       = A*(1 + 0.03)^(2*n) = A*(1.03)^(2n)

And we want that this is equal to $80,000 when n = 13 (remember that when n = 13, the child will be 18 years old)

M(13) = A*(1.03)^(2*18) = $80,000

           A = $80,000/((1.03)^(2*18)) = $27,602.60

Then they should deposit $27,602.60 now to meet their financial goal when the child is 18.

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If the farmer has 234 feet of fencing, what are the dimensions of the region which enclose the maximal area?
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Answer: 58 ft × 58 ft  

Step-by-step explanation:

Let the length of the region = x feet

And, the width of the region = y feet

Since, the perimeter of the region = 234 feet ( Given )

⇒ 2(x+y) = 234

⇒ x+y = 117

⇒ y = 117 - x

Again the area of the region, A = xy

⇒ A(x) = x(117-x)

⇒ A(x) = 117x - x^2

By differentiating the above equation with respect to x,

⇒ A'(x) = 117 - 2x  

For maxima or minima,

A'(x) = 0

\implies 117 - 2x = 0

\implies -2x = -117

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Again differentiating equation A'(x) with respect to x,

We get, A''(x) = -2

Hence, For x = 58.5 A''(x) = negative

⇒ For x = 58.5 feet the area A(x) is maximum,

⇒ The length of the region having maximum area = x = 58.5 feet

And, the width of the region having maximum area = y = 117-x= 117 - 58.5=58.5 feet,

⇒ The dimension of the region having the maximum area = 58.5 ft × 58.5 ft

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