The point r(-6,-5) lies on the circle.
Explanation
Given that the center of the circle=(-2,-2)
diameter=10 units
we have to determine which point among the given points lies on the circle.
radius=diameter/2=10/2=5 units
let (x,y) be a point on the circle
The distance between the center and (x,y) is equal to the radius of the circle
The distance between them=
squaring both sides 
The option (-6,-5) satisfies the equation
therefore the point that lies on the circle is (-6,-5)
Answer:
its either 19.25 or 22.75
Step-by-step explanation:
Answer:
5th term of sequence = -18
nth term of the sequence = -5n + 7
Step-by-step explanation:
Difference between successive and previous term of the output,
= -3 - 2
= -5
Similarly, 
= -5
There is a common difference 'd' = (-5)
Therefore, the sequence formed will be an arithmetic sequence.
First term of the sequence 'a' = 2
Explicit formula of an arithmetic sequence,
= a + (n - 1)d [n = input value]
= 2 + (n - 1)(-5)
= 2 - 5n + 5
= -5n + 7
5th term of this sequence,

= 2 - 20
= -18
Therefore, 5th term of sequence = -18
nth term of the sequence = -5n + 7
Answer:
39.5 ft
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you of the relation between angles and sides of a right triangle.
Tan = Opposite/Adjacent
This lets us write two equations in two unknowns:
tan(67°) = AD/CD . . . . . . . . . . angle at guy point
tan(39°) = AD/(CD+32) . . . . . .angle 32' farther
__
Solving the first equation for CD and using that in the second equation, we can get an equation for AD, the height of the tower.
CD = AD/tan(67°)
tan(39°)(CD +32) = AD . . . . eliminate fractions in the second equation
tan(39°)(AD/tan(67°) +32) = AD
32·tan(39°) = AD(1 -tan(39°)/tan(67°)) . . . simplify, subtract left-side AD term
32·tan(39°)tan(67°)/(tan(67°) -tan(39°)) = AD . . . . divide by AD coefficient
AD ≈ 39.486 . . . . feet
The tower is about 39.5 feet high.
Answer:
test statistic (Z) is 2.5767 and p-value of the test is .009975
Step-by-step explanation:
: percentage of students who smoke did not change
: percentage of students who smoke has changed
z-statistic for the sample proportion can be calculated as follows:
z=
where
- p(s) is the sample proportion of smoking students (
=0.25)
- p is the proportion of smoking students in the survey conducted five years ago (18% or 0.18)
- N is the sample size (200)
Then, z=
≈ 2.5767
What is being surveyed is if the percentage of students who smoke has changed over the last five years, therefore we need to seek two tailed p-value, which is .009975.
This p value is significant at 99% confidence level. Since .009975 <α/2=0.005, there is significant evidence that the percentage of students who smoke has changed over the last five years