Answer:
Weight of the truck=9408 N
Step-by-step explanation:
Boat is experiencing the buoyant force as it is in the water and is sinking
According to the force balance in y direction. As both is floating, two forces balance each other:
where:
is the buoyant force
is the weight=mg
Eq (1)
Buoyant force is equal to the mass of water displaced * gravitational acceleration.
Taking density of water to be 1000 Kg/m^3
From Eq(1):
Weight of the truck=9408 N
Answer:
Step-by-step explanation:
1 ) Given that
For a non homogeneous part , we assume the particular solution is
2 ) Given that
For a non homogeneous part , we assume the particular solution is
3 ) Given that
y′′ + 4y′ + 20y = −3sin(2x)
For a non homogeneous part −3sin(2x) , we assume the particular solution is
4 ) Given that
y′′ − 2y′ − 15y = 3xcos(2x)
For a non homogeneous part 3xcos(2x) , we assume the particular solution is
Answer:
0 and 5 minutes
Step-by-step explanation:
Median is the middle observation of given data. It can be found by following steps:
Arranging data in ascending or descending order.
Taking the average of middle two value if the total number of observation is even, and this average is our median.
or, if we odd number of observation then the most middle value is our median.
The mode is the observation which has a high number of repetitions (frequency).
We have given 8 numbers and we have to find the other two numbers a minute late for each bus to arrive at the bus stop.
Also, we have given the median and mode of all 10 buses i.e. 3.5 and 0 respectively.
Since the mode is 0, so the frequency of 0 must be greater than 2 times and less than or equal to 4 times.
The frequency of 0 is 4 is not possible as then we didn't get a median 3.5 then.
So the frequency of 0 is 3.
Hence one of number is 0 in two unknown number of a minute late for each bus arrive at the bus stop.
Now, we have the number of minutes late for each bus after arranging them in ascending order is: 0 0 0 2 2 6 8 8 9
For getting a median 3.5 we must have a number between 2 and 6. Let it be x then:
⇒x = 5
Hence the number of minutes late for each bus is: 0 0 0 2 2 5 6 8 8 9
Thus, 0 and 5 are minutes late for the two-afternoon buses.