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enot [183]
1 year ago
14

What additional information could be used to prove that ΔXYZ ≅ ΔFEG using ASA or AAS? Check all that apply. ∠Z ≅ ∠G and XZ ≅ FG

∠Z ≅ ∠G and ∠Y ≅ ∠E XZ ≅ FG and ZY ≅ GE XY ≅ EF and ZY ≅ FG ∠Z ≅ ∠G and XY ≅ FE
Mathematics
2 answers:
Fofino [41]1 year ago
6 0

Answer:

1 & 5

Step-by-step explanation:

i know da way

Alla [95]1 year ago
4 0

Answer:

The answer is A and E.

A.∠Z ≅ ∠G and XZ ≅ FG

E.∠Z ≅ ∠G and XY ≅ FE

Step-by-step explanation:

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The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillat
Greeley [361]

Answer:

1) L \propto T^2

Using the condition given:

2.205 m = K (3)^2

K = 0.245 \approx \frac{g}{4\pi^2}

So then if we want to create an equation we need to do this:

L = K T^2

With K a constant. For this case the period of a pendulumn is given by this general expression:

T = 2\pi \sqrt{\frac{L}{g}}

Where L is the length in m and g the gravity g = 9.8 \frac{m}{s^2}.

2) T = 2\pi \sqrt{\frac{L}{g}}

If we square both sides of the equation we got:

T^2 = 4 \pi^2 \frac{L}{g}

And solving for L we got:

L = \frac{g T^2}{4 \pi^2}

Replacing we got:

L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m

3) T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s

Step-by-step explanation:

Part 1

For this case we know the following info: The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillation), T seconds.

L \propto T^2

Using the condition given:

2.205 m = K (3)^2

K = 0.245 \approx \frac{g}{4\pi^2}

So then if we want to create an equation we need to do this:

L = K T^2

With K a constant. For this case the period of a pendulumn is given by this general expression:

T = 2\pi \sqrt{\frac{L}{g}}

Where L is the length in m and g the gravity g = 9.8 \frac{m}{s^2}.

Part 2

For this case using the function in part a we got:

T = 2\pi \sqrt{\frac{L}{g}}

If we square both sides of the equation we got:

T^2 = 4 \pi^2 \frac{L}{g}

And solving for L we got:

L = \frac{g T^2}{4 \pi^2}

Replacing we got:

L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m

Part 3

For this case using the function in part a we got:

T = 2\pi \sqrt{\frac{L}{g}}

Replacing we got:

T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s

8 0
2 years ago
Use the formula t=ln2/k that gives the time for a population, with a growth rate k, to double, to answer the following question.
Arturiano [62]

Answer:

  • k = 0.005
  • doubling time ≈ 139 years

Step-by-step explanation:

Matching the form

  A = A0·e^(kt)

to the given equation

  A = 8·e^(.005t)

we can identify the value of k as being 0.005.

  k = 0.005

___

The doubling time is given by the formula ...

  t = ln(2)/k = ln(2)/0.005 ≈ 138.63

It will take about 139 years for the population to double.

3 0
2 years ago
Your utility company charges 11 cents per​ kilowatt-hour of electricity. Complete parts​ (a) and​ (b) below. a. What is the dail
Colt1911 [192]

Answer:

a. 9.9 cents

b. 26.5 dollars

Step-by-step explanation:

The first thing they mention to us is the cost of energy 11 cents / kwh

a) In the first point they ask us to calculate the daily cost of keeping the flashlight on for 12 hours, they tell us that it consumes 75 watts per hour, but this value must be passed to kW because the cost is given in kWh

to pass it, it would be: 75 watt * 1 kw / 1000 watt = 0.075 kw,

the formula to apply would be like this:

Daily cost = flashlight cost * time * energy cost

we all know them so we replace:

Daily cost = 0.075 kw * 12 h * 11 cents / kwh = 9.9 cents

b) Now, to know the annual savings, we must calculate the difference between the expense of the normal flashlight and the LED, let's calculate the daily cost of the LED, like this:

20 watt * 1 kw / 1000 watt = 0.02 kw

Daily cost = 0.02 kw * 12 h * 11 cents / kwh = 2.64 cents

Now by calculating the difference we multiply by 365 which are the days of a year.

Savings / year = (9.9 - 2.64) * 365 = 2649.9 cents = 26.5 dollars.

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2 years ago
Which number is located between 1.2 and 1.4 on the number line
Zina [86]

Answer:1.3

Step-by-step explanation:

6 0
2 years ago
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A company that makes fleece clothing uses fleece produced from two farms, Northern Farm and Western Farm. Let the random variabl
dusya [7]

Answer:

i think its D. C. or E. I'm not that great in math im kind of struggling thru it

7 0
2 years ago
Read 2 more answers
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