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Serhud [2]
2 years ago
3

In a right triangle, if ∠θ=45° and the side opposite to this angle is 5√2 meters, what is the approximate length of the hypotenu

se?
Mathematics
2 answers:
Scilla [17]2 years ago
7 0
Sine 45 degrees = opp / hyp
hypotenuse = 5*sqrt(2) / sine(45)
hypotenuse = 5*sqrt(2) /.70711
hypotenuse = <span> <span> <span> 9.9999544793 </span> </span> </span>
hypotenuse is 10.


Pachacha [2.7K]2 years ago
5 0

Answer:

<h2>The hypothenuse is 10 meters long.</h2>

Step-by-step explanation:

We know by defintion that a right triangle has a righ angle which is equal to 90°.

So, by given, we know that one of the acute angles is 45°, that means the other acute angle is also 45°, because all three internal angles must sum 180°.

Now, the given angle is

\theta =45\°

And its opposite side is 5\sqrt{2}.

To find the hypothenuse we need to use the sin function, which relates the angle with its opposite side and the hypothenuse.

sin \theta =\frac{opposite}{hypothenuse}\\ sin 45\°=\frac{5\sqrt{2} }{h}

Now, we solve for h

h=\frac{5\sqrt{2} }{sin45\°}\\ h=\frac{5\sqrt{2} }{\frac{\sqrt{2} }{2} } \\h=\frac{10\sqrt{2} }{\sqrt{2} }\\ h=10

Thereofre, the hypothenuse is 10 meters long.

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A sports company wants to package a ball with a 1.5-inch radius in sets of two. They have two options: a cylinder or a square pr
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Step 1

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In this problem we have

r=1.5\ in

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V=\frac{4}{3} \pi 1.5^{3}=4.5\pi\ in^{3}

so

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V=2*4.5\pi=9 \pi\ in^{3}

Step 2

Find the volume of a cylinder

we know that

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V=\pi r^{2}h

In this problem we have

r=1.5\ in

h=4*r=4*1.5=6\ in    

Substitute

V=\pi (1.5^{2})(6)=13.5 \pi\ in^{3}

Step 3

Find the amount of wasted space in the cylinder

Subtract the volume of the two balls from the volume of the cylinder

13.5\pi\ in^{3}-9\pi\ in^{3}=4.5\pi\ in^{3}=14.14\ in^{3}    

Step 4

Find the volume of the square prism

The volume of the prism is equal to

V=Bh

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B is the area of the base of the prism

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In this problem we have

B=(2*1.5)^{2}=9\ in^{2} -----> the base is equal to the diameter    

h=4*r=4*1.5=6\ in  

Substitute

V=9*6=54\ in^{3}

Step 5

Find the amount of wasted space in the prism

Subtract the volume of the two balls from the volume of the prism

54\ in^{3}-9\pi\ in^{3}=25.73\ in^{3}  

Step 6

Compare the amount of wasted space

the amount of wasted space in the cylinder is 14.14\ in^{3}

the amount of wasted space in the prism is  25.73\ in^{3}

Find the difference

25.73\ in^{3}-14.14\ in^{3}=11.59\ in^{3}=11.6\ in^{3}

The package that has the least amount of wasted space is the cylinder

therefore

<u>the answer is the option</u>

the cylinder because it has approximately 11.6 in.3 less wasted space than the prism

5 0
2 years ago
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Answer:

He is missing 1500, the final solution would be 2090

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