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Rasek [7]
1 year ago
8

LCM of a2+b2 and a4-b4​

Mathematics
1 answer:
Zarrin [17]1 year ago
4 0

Answer:

The LCM is:

(a^2+b^2)(a+b)(a-b)

Step-by-step explanation:

Given polynomials are:

a^2+b^2\\a^4 - b^4

We can use factorization to find the LCM of the given polynomials.

Taking the second polynomial, using the identity

a^2 - b^2 = (a+b)(a-b)

Applying on 2nd polynomial

(a^2)^2-(b^2)^2\\=(a^2+b^2)(a^2-b^2)\\=(a^2+b^2)(a+b)(a-b)

We can see that a^2+b^2 is common in both polynomials, it will be counted only one time. The LCM of given polynomials is:

(a^2+b^2)(a+b)(a-b)

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a small table is 2 feet by 3 feet a large table is twice as long and rwice as wide as the small table. Whats the area of the lar
Scorpion4ik [409]

Answer:

The area of larger table is 24 square feet.

Step-by-step explanation:

Given are the length and width of small table

l_s = 2\ ft\\w_s = 3\ ft

The area of a rectangular table is calculated by multiplying the length and width. It is also given that the length and width of the larger table is double the length and width of small table

So the length and width of larger table will be:

l_l = 2*2 = 4\ feet\\w_l = 3*2 = 6\ feet

The area of larger table will be:

A_l = l_l*w_l\\= 4 * 6\\=24\ ft^2

Hence,

The area of larger table is 24 square feet.

7 0
1 year ago
Sociologists studying the behavior of high school freshmen in a certain state collected data from a random sample of freshmen in
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Step-by-step explanation:

Stay safe hope this helps

5 0
2 years ago
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Consider 7 x 10 ^ 3 write a pattern to find the value of the expression
Lelechka [254]
7 x 10^1 = 70
7 x 10^2 = 700
7 x 10^3 = 7000
3 0
2 years ago
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In electrical engineering, the unwanted "noise" in voltage or current signals is often modeled by a Gaussian (i.e., normal) dist
vladimir1956 [14]

Answer:

Cov(X, Y) =0.029.

Step-by-step explanation:

Given that :

The noise in a particular voltage signal has a constant mean of 0.9 V. that is μ = 0.9V ............(1)

Also, the two noise instances sampled τ seconds apart have a bivariate normal distribution with covariance.

0.04e–jτj/10 ............(2)

Having X and Y denoting the noise at times 3 s and 8 s, respectively, the difference of time = 8-3 = 5seconds.

That is, they are 5 seconds apart,

τ = 5 seconds..............(3)

Thus,

Cov(X, Y), for τ = 5seconds = 0.04e-5/10

= 0.04e-0.5 = 0.04/√e

= 0.04/1.6487

= 0.0292

Thus, Cov(X, Y) =0.029.

5 0
2 years ago
High-power experimental engines are being developed by the Stevens Motor Company for use in its new sports coupe. The engineers
mamaluj [8]

Answer:

The 95% confidence interval the average maximum power is (596.0 to 644.0)

Step-by-step explanation:

Average maximum of the sample = x = 620 HP

Standard Deviation = s = 45 HP

Sample size = n = 16

We have to calculate the 95% confidence interval. The value of Population standard deviation is unknown, and value of sample standard deviation is known. Therefore, we will use one sample t-test to build the confidence interval.

Degrees of freedom = df = n - 1 = 15

Critical t-value associated with 95% confidence interval and 15 degrees of freedom, as seen from t-table = t_{\frac{\alpha}{2}} = 2.131

The formula to calculate the confidence interval is:

(x-t_{\frac{\alpha}{2} } \times \frac{s}{\sqrt{n} }, x+t_{\frac{\alpha}{2} } \times \frac{s}{\sqrt{n} })

We have all the required values. Substituting them in the above expression, we get:

(620-2.131 \times \frac{45}{\sqrt{16} }, 620+2.131 \times \frac{45}{\sqrt{16} })\\\\ =(596.0 , 644.0)

Thus, the 95% confidence interval the average maximum power is (596.0 to 644.0)

7 0
2 years ago
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