Question

A new company is hiring employees rapidly. every day, the number of employees doubles in size. if it takes 48 days for the company to be at full capacity, how many days would it take for the company to be at half capacity?

Answer 1

Base from the problem the doubling size of the company is one day. and it takes 48 days for the company to to be at full capacity. since the doubling rate is one day, so meaning a day before the company was full, the company is half of its capacity. so the answer is 47 days

Answer 2

Let

x----> the number of employees in the day 48

we know that

A geometric sequence is a sequence in which each term is found by multiplying the preceding term by the same value

so

$a(n+1)=an*r$

in this problem

$r=2 \\ \\ a48=x$

$a48=a47*2\\ \\ a47=\frac{x}{2}$

that means that for the day $47$ the numbers of employees in a new company is at half of the full capacity

therefore

the answer is

$47 days$