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lyudmila [28]
2 years ago
4

You are paid $9.25/hr at your part-time job. You work for 10 hr/wk. You are considering changing jobs so you can work 15 hr/wk,

but the pay is $7.15/hr with tips that average $3.00/hr. How much more per week can you make by switching jobs?
Mathematics
2 answers:
padilas [110]2 years ago
7 0

Answer:

Hence, we will get $ 59.75 more in the  new job in one week.

Step-by-step explanation:

You are paid $9.25/hr at your part-time job.

You work for 10 hr/wk.

so, the amount he gets in 1 week=$ (9.25×10)=$ 92.5

You are considering changing jobs so you can work 15 hr/wk, but the pay is $7.15/hr with tips that average $3.00/hr.

so, the amount he gets in his new job in 1 week is:

(7.15×15)+(3×15)

=107.25+45

=$ 152.25

Hence, the difference in amount is:

152.25-92.5

=$ 59.75

Hence, we will get $ 59.75 more in the new job in one week.

mr Goodwill [35]2 years ago
6 0
59.75 152.25-92.50= 59.75
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2 years ago
In a sale, normal prices are reduced by 13%. The sale price of a DVD recorder is £108.75 Calculate the normal price of the DVD r
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A study of immunizations among school‑age children in California found that some areas had rates of unvaccinated school‑age chil
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Answer:

Probability that none of the 20 children in such a classroom would be unvaccinated is 0.055.

Step-by-step explanation:

We are given that a classroom of 20 children in one such area where 13.5% of children are unvaccinated.

If there are no siblings in the classroom, we are willing to consider the vaccination status of the 2020 unrelated children to be independent.

The above situation can be represented through binomial distribution;

P(X=r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,......

where, n = number of trials (samples) taken = 20 children

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<u><em>Let X = Number of children that are unvaccinated</em></u>

So, X ~ Binom(n = 20, p = 0.135)

Now, Probability that none of the 20 children in such a classroom would be unvaccinated is given by = P(X = 0)

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                          =  0.055

<em>Hence, the probability that none of the 20 children in such a classroom would be unvaccinated is 0.055.</em>

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