F = 100(.5736)
<span>= 57.36 lbs. (rounded off to 2 decimal places) </span>
<span>2) sin60 = .866 </span>
<span>F = 18(.866) </span>
<span>= 15.59 lbs. (rounded off to 2 decimal places)</span>
<h2>
Answer:</h2>
PART A:
$ 1.80558
PART B:
$ 27.59958
<h2>
Step-by-step explanation:</h2>
- The price of an all-access ticket to the fair is $42.99 before tax.
Also,
- Roland bought the all-access ticket for 40% off.
i.e. he will have to pay (100-40)%=60% of the amount of the actual ticket.
This means that the price of ticket after the offer will be:

Hence, discounted price=$ 25.794
- Now, Ronald has to pay 7% sales tax on the discounted price.
i.e.
he has to pay 7% tax on 25.794
i.e.

PART A:
Hence, the amount of sales tax=$ 1.80588
PART B:
The total amount that he will pay for the ticket is:
Amount of tax+Discounted price
= 1.80558+25.794
= $ 27.59958
Answer:
$2000
Step-by-step explanation:
Given data
We are given that the price of the super PC is $2000
Since they are buying only one of the super PC they will have to pay
$2000
Hence option C is the correct answer