Answer:
a. y equals one third times x plus 10
= y = 1/3(x) + 10
Step-by-step explanation:
Let us represent:
Let the original final plan = x
Let the current flight plan = y
The initial time of departure = 4.00pm
Her flight was then delayed for 10 minutes
We are told in the question that:
The current flight plan allows her arrive at her destination three times faster.
This means y= (1/3)x
y = x/3
Hence the equation generated =
y = x/3 +10
y = 1/3(x) + 10
We know that
volume of <span>a rectangular prism =B*h------> equation 1
where
B is the area of the base
h is the height
volume of </span><span>a rectangular pyramid=(1/3)*B*h-----> equation 2
where
</span>B is the area of the base
h is the height
<span>
substitute equation 1 in equation 2
</span>volume of a rectangular pyramid=(1/3)*volume of a rectangular prism
<span>
the answer part a) is
</span>volume of a rectangular pyramid=(1/3)*volume of a rectangular prism
<span>
Part b) </span><span>If the pyramid was full of water, how much of the prism would it fill up?
</span>
the answer part b) is
<span>If the pyramid was filled with water, the prism would only fill 1/3 of its volume
Part c) </span><span>Name another pair of three-dimensional objects that have a relationship similar to this
cones and cylinders
</span>volume of a cylinder =B*h------> equation 1
where
B is the area of the base
h is the height <span>
</span>volume of a cone=(1/3)*B*h-----> equation 2
where
B is the area of the base
h is the height
substitute equation 1 in equation 2
volume of a cone=(1/3)*volume of a cylinder
Answer:
Plane A and QRV intersection line is QR.
Explanation:
The plane QRV contains the rectangle QRVN. This rectangle intersects the plane A in the line QR.
Plane A and QRV intersection line is QR.
If one knows a specific line in one plane (for example, two points in the plane), and this line intersects the other plane, then its point of intersection.
Thus, it is on the line of intersection for the two planes.
There is a missing graph in the problem given. However, we can simply solve the equation using the given data.
Items to be sold: scarves and hats. Minimum of 20 items sold in all.
Scarves sell for 10 each and hats sell for 20 each. Must sell at least 300 worth of merchandise to make profit.
Let s represent scarves and h represent hats.
10s + 20h <u>></u> 300
s + h <u>></u> 20
We use inequality because the problem states "at least".
s + h = 20
10s + 20h = 300
s = 20 - h
10(20-h) + 20h = 300
200 - 10h + 20h = 300
10h = 300 - 200
10h = 100
h = 100/10
h = 10
s = 20 - h
s = 20 - 10
s = 10
s + h <u>></u> 20
10 + 10 <u>></u> 20
10s + 20h <u>></u> 300
10(10) + 20(10) <u>></u> 300
100 + 200 <u>></u> 300
Answer:
8 weeks is the right APEX ANSWER
