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2 years ago

How to I solve this please help!!! I will give Brainliest.

Mathematics

2 answers:

worty [1.4K]2 years ago

8 0

Answer:

x is 35

Step-by-step explanation:

First do 180 -40 and get 140. Then add 3x plus x to get 4x because they are the same value/ Do 140/ 4x and get 35. X equals 35.

Arlecino [84]2 years ago

6 0

Answer:

35, 135

Step-by-step explanation:

You first add the like terms. 3x + x = 4x. Next you form an inequality.

40 - 4x = 180.

x = 35

Since x equals 35 you do 3 * 35. 3(35), which is 105.

35 + 40 + 105 = 180!

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People enjoyed attending the concert in the park. Twice as many men as women attended the concert. If the total attendance was 7

vazorg [7]

Hello! A way we could solve this equation is to divide 714 by three and then multiply the quotient by 2 to get the number of men that attended. 714/3 is 238. There were 238 women that attended the concert. 238 * 2 is 476. 476 + 238 = 714. There. There were 476 men that attended the concert.

5 0

2 years ago

Read 2 more answers

It costs 20 cents to receive a photo and 30 cents to send a photo from a cellphone. C is the cost of one photo (either sent or r

ddd [48]

Answer:

(a) PC(C)= $\left \{ {{0.6 \ \ \ \ x=20} \atop 0.4 \ \ \ \ {x=30}} \right. \\\ 0 \ \ \ \ \ \ \ else$

(b) E[C] = 24 cents

Step-by-step explanation:

Given:

Cost to receive a photo = 20 cents

Cost to send a photo = 30 cents

Probability of receiving a photo = 0.6

Probability of sending a photo = 0.4

We need to find

(a) PC(c)

(b) E[C]

Solution:

(a)

PC(C)= $\left \{ {{0.6 \ \ \ \ c=20} \atop 0.4 \ \ \ \ {c=30}} \right. \\\ 0 \ \ \ \ \ \ \ else$

(b)

Expected value can be calculated by multiplying probability with cost.

E[C] = Probability × cost

E[C] = $0.6\times20 +0.4 \times 30 = 12 + 12 = 24\ cents$

3 0

2 years ago

Arrange the entries of matrix A in increasing order of their cofactors values

givi [52]

To find the cofactor of

$A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]$

We cross out the Row and columns of the respective entries and find the determinant of the remaining $2\times 2$ matrix with the alternating signs.

$Ac_{11}=\left|\begin{array}{ccc}4&-1\\2&1\end{array}\right|$

$Ac_{11}=4\times 1- -1\times 2$

$Ac_{11}=4+ 2$

$Ac_{11}=6$

$Ac_{12}=-\left|\begin{array}{ccc}-7&-1\\-8&1\end{array}\right|$

$Ac_{12}=-(-7\times 1- -1\times -8)$

$Ac_{12}=-(-7- 8)$

$Ac_{12}=15$

$Ac_{21}=-\left|\begin{array}{ccc}5&3\\2&1\end{array}\right|$

$Ac_{21}=-(5\times 1- 3\times 2)$

$Ac_{21}=-(5-6)$

$Ac_{21}=1$

$A_c{23}=-\left|\begin{array}{ccc}7&5\\-8&2\end{array}\right|$

$Ac_{23}=-(7\times 2 -8\times 5)$

$Ac_{23}=-(14-40)$

$Ac_{23}=26$

$A_c{31}=\left|\begin{array}{ccc}5&3\\4&-1\end{array}\right|$

$Ac_{31}=5\times -1 -4\times 3$

$Ac_{31}=-5-12$

$Ac_{31}=-17$

$A_c{33}=\left|\begin{array}{ccc}7&5\\-7&4\end{array}\right|$

$Ac_{33}=7\times 4- -7\times 5$

$Ac_{33}=28+35$

$Ac_{33}=63$

Therefore in increasing order, we have;

$Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63$

7 0

2 years ago

Read 2 more answers

The graph of f(x), shown below has the same shape as the graph has the same shape as the graph of g(x)=x^4-X^2 which contains th

Alenkasestr [34]

First of all it is always a good idea to graph a question like this one. Here are the three graphs

y = x^4 - x^2 Color: Red This is the base graph
y = x^4 - x^2 - 4 Color Blue This has - 4 added to it.
y = x^4 - x^2 + 4 Color Green This has 4 added to the base graph

Which one is correct? The red and blue one are not. The graph you want is plotted upward from the base graph. The base graph (red nothing added to it) is not right because it has points on the x axis. The graph you want does not.

The same is true of the blue graph. It cuts the x axis. That only leaves the green one.

Answer: C