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Marina86 [1]
2 years ago
12

A line passes through the point (0, –1) and has a positive slope. Which of these points could that line pass through? Check all

that apply.
(12,3)
(-2,-5)
(-3,1)
(1,15)
(5,-2)
Mathematics
2 answers:
exis [7]2 years ago
8 0

D & E

Step-by-step explanation:

(-3,1) (5,-2)

Semmy [17]2 years ago
7 0

Answer:

(12,3)    (-2,-5)    (1,15)

Step-by-step explanation:

I graphed each point out to find this answer :)

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Jerry's Fish Shack claims that 16% of its employees are late to work once a week. The manager surveyed 25 employees and found th
larisa86 [58]

Answer:

We need to conduct a hypothesis in order to test the claim that the true proportion of employess are late to work is 0.16, so we need to apply a one sample proportion test:  

Null hypothesis:p=0.16  

Alternative hypothesis:p \neq 0.16  

z=\frac{0.20 -0.16}{\sqrt{\frac{0.16(1-0.16)}{25}}}=0.546  

p_v =2*P(z>0.546)=0.585  

Step-by-step explanation:

Data given and notation

n=25 represent the random sample taken

\hat p=0.2 estimated proportion  

p_o=0.16 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of employess are late to work is 0.16, so we need to apply a one sample proportion test:  

Null hypothesis:p=0.16  

Alternative hypothesis:p \neq 0.16  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.20 -0.16}{\sqrt{\frac{0.16(1-0.16)}{25}}}=0.546  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z>0.546)=0.585  

4 0
2 years ago
100/225 square feet of your bakery will be used as your storefront, where customers come visit. The rest kill be used for storag
Lelu [443]
The answer is 5/9. I showed a bit more work on the other post
7 0
2 years ago
It cost Naomi $7.70 to send 154 text messages. How many text messages did she send
s2008m [1.1K]

You have to find the unit rate

SO..

7.70 / 154 = 0.05

So it cost her 0.05 cents for each text.

So then you divide $ 5.25 by the unit rate to get the number of text

5.25 /0.05 = 105

so she sent 105 text

To check it you just multiply the unit rate by the number of text you got and you show come up with $ 5.25

0.05 x 105 = 5.25

4 0
2 years ago
Write each fraction as a sum of unit fractions 7/10
seropon [69]

Answer:

3/10+4/10=7/10

Step-by-step explanation:

8 0
2 years ago
A bridge hand in which there is no card higher than a nine is called a Yarborough. Specify an appropriate sample space and deter
Vilka [71]

Answer:

The probability of Yarborough when you are randomly dealt 13 cards out of a well-shuffled deck of 52 card is 0.000547.

Step-by-step explanation:

The number of ways you  can choose a set of 13 different cards from a deck of 52 cards is given by 52P13.

Hence the unordered sample space has 52P13 equally likely outcomes. The number of outcomes with no card above a nine is 32P13.

This leads to the same value for the desired probability of a Yarborough:

32P13 / 52P13  = 0.000547.

3 0
2 years ago
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