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allsm [11]
2 years ago
8

Lot 1 lies where two roads meet at a 79° angle. Lot 2 lies where two roads meet at a 65° angle. Lot 3 lies where two roads meet

at a 36° angle. All lots have two sides measuring 20 feet as shown. A triangle is shown. At each of the points of the triangle, a line representing a fence is drawn to form a smaller triangle at each point. All other sides of the smaller triangles are 20 feet. Lot 1 lies where the angle is 79 degrees. Lot 2 lies where the angle is 65 degrees. Lot 3 lies where the angle is 36 degrees. A fence runs along the back wall of each property, as shown in the diagram. Which lot has the longest fence along the back wall? Which lot has the shortest fence along the back wall?
Mathematics
2 answers:
fiasKO [112]2 years ago
8 0

Answer: First is Lot 1

Second is Lot 3

Step-by-step explanation:

a_sh-v [17]2 years ago
5 0

Answer:

First answer is Lot 1

Second Answer is Lot 3

Step-by-step explanation:

You might be interested in
A snowboarder leaves an 8-foot-tall ramp with an upward velocity of 28 feet per second. The function h   16t 2  28t 8 gives
mr_godi [17]

The complete question is;

A snowboarder leaves an 8-foot-tall ramp with an upward velocity of 28 feet per second. The function h = -16t² + 28t + 8 gives the height h (in feet) of the snowboarder after t seconds. The snowboarder earns 1 point per foot of the maximum height reached, 5 points per second in the air, and 25 points for a perfect landing. With a perfect landing, how many total points does the snowboarder receive?

Answer:

Total points earned with a perfect landing = 111 points

Step-by-step explanation:

First of all, let's find the maximum height of the given parabolic function h = -16t² + 28t + 8

h_max = c - (b²/4a)

where: a = -16, b = 28, c = 8

h_max = 8² - 28²/(4*(-16))

h_max = 64 + 784/64

h max = 76.25 ft ≈ 76 ft

The question says that the snowboarder earns 1 point per foot of the maximum height reached.

Thus, the points from the maximum height reached are 76 points

Now, let's find the maximum time in air by solving the equation for h = 0 Thus;

-16t² + 28t +8 = 0

Using quadratic formula,

t = [-28 ± √(28² - (4*-16*8))]/(2*-16)

t = 2 or -0.25

We'll use 2 as we are looking for maximum time.

The question says at maximum time, it's 5 points for each second in the air,

thus, points for seconds in air = 5 × 2 = 10 points

We are told 25 points for perfect landing.

Thus,

Total points earned with a perfect landing = 76 + 10 + 25 = 111 points

7 0
2 years ago
Solve x2 = 12x – 15 by completing the square. Which is the solution set of the equation?
Nady [450]
For this case we have the following polynomial:
 x ^ 2 = 12x - 15

 The first thing to do is to place the variables on the same side of the equation.
 We have then:
 x ^ 2 - 12x = -15

 We complete the square by adding the term (b / 2) ^ 2 on both sides of the equation.
 We have then:
 x ^ 2 - 12x + (-12/2) ^ 2 = -15 + (-12/2) ^ 2

 Rewriting we have:
 x ^ 2 - 12x + (-6) ^ 2 = -15 + (-6) ^ 2

x ^ 2 - 12x + 36 = -15 + 36
 
(x-6) ^ 2 = 21
 x-6 =+/- \sqrt{21}
 Therefore, the solutions are:
 x = 6 - \sqrt{21}
 x = 6 + \sqrt{21}
 Answer:
 
the solution set of the equation is:
 
x = 6 - \sqrt{21}
 x = 6 + \sqrt{21}
3 0
2 years ago
Read 2 more answers
jim says that the output of the floor function is the number before the decimal point in the input. For what domain is Jim’s sta
Mila [183]

Jim’s statement is correct for all numbers greater than or equal to 0. It does not work for negative numbers. For example, the floor of –3.5 is –4, where –4 is not equal to –3, the number before the decimal point. Hope this helps!

Thanks!

-Charlie

7 0
2 years ago
Read 2 more answers
If you apply the changes below to the quadratic parent function, f(x) = x2, what is the equation of the new function? Shift 3 un
Alex17521 [72]
To apply the changes to the equation of a vertical stretch of 4 and a translation of 3 units to the right, as well as the correct answer would be choice B.

The reason for this is when you apply a vertical stretch, because it changes the y-values (which causes it to vertically stretch or appear skinnier when graphed), you would multiply 4 to f(x) which would look like 4x^2.

Then, since you have a reflection over the x-axis, you must multiply a -1 to f(x) to reflect it over the x-axis which would result in -4x^2.

Finally, it also asks to shift the graph right 3 which by moving it right, you change the x values meaning you will perform f(x-3) to achieve this (subtract the value from x when you move right, and add the value to x when you move left).

This therefore results in your answer, the new graph would be
g(x)= -4(x-3)^2 or choice B.
8 0
2 years ago
The XO Group Inc. conducted a survey of 13,000 brides and grooms married in the United States and found that the average cost of
slavikrds [6]

Answer:

a) 0.0392

b) 0.4688

c) At least $39,070 to be among the 5% most expensive.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 29858, \sigma = 5600

a. What is the probability that a wedding costs less than $20,000 (to 4 decimals)?

This is the pvalue of Z when X = 20000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

So this probability is 0.0392.

b. What is the probability that a wedding costs between $20,000 and $30,000 (to 4 decimals)?

This is the pvalue of Z when X = 30000 subtracted by the pvalue of Z when X = 20000.

X = 30000

Z = \frac{X - \mu}{\sigma}

Z = \frac{30000 - 29858}{5600}

Z = 0.02

Z = 0.02 has a pvalue of 0.5080.

X = 20000

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

So this probability is 0.5080 - 0.0392 = 0.4688

c. For a wedding to be among the 5% most expensive, how much would it have to cost (to the nearest whole number)?

This is the value of X when Z has a pvalue of 0.95. So this is X when Z = 1.645.

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 29858}{5600}

X - 29858 = 5600*1.645

X = 39070

The wedding would have to cost at least $39,070 to be among the 5% most expensive.

5 0
2 years ago
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