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Zigmanuir [339]
2 years ago
15

Examine A ABC below.

Mathematics
1 answer:
Roman55 [17]2 years ago
8 0

Answer:

  • DE║AC

Step-by-step explanation:

<u>Given relationships:</u>

DE = 2 AC

  • Incorrect. Should be DE = 1/2 AC

DE║AC

  • Correct

m∠BCA = 2(m∠BED)

  • Incorrect. Should be m∠BCA = m∠BED

DE = AC

  • Incorrect. Should be DE = 1/2 AC
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A recent poll of 124 randomly selected residents of a town with a population of 310 showed that 93 of them are opposed to a new
tester [92]
The sample size is 124.
93 of them are opposed to new shopping center.

So, 
n = 124
p = \frac{93}{124}=0.75

The point estimate of the population proportion = p = 0.75
q = 1 - p = 0.25

Margin of error (E) can be calculated by:

E= Z_{c}  \sqrt{ \frac{pq}{n} }

Using the values, we get:

E=1.645 \sqrt{ \frac{0.75*0.25}{124} }=0.06

Therefore, the margin of error is approximately 0.06 or 6%.
6 0
2 years ago
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93 27 14 what is next in the sequence?
Assoli18 [71]

Answer:

4

Step-by-step explanation:

9×3=27

2×7=14

1×4=4

nice logic

6 0
2 years ago
The profits for a business can be represented as a function p(x)=110+25x for the month of January and q(x)=15x+85 for the month
mrs_skeptik [129]
To find the total profit, add p(x) and q(x):
(110 + 25x) + (15x + 85)
15x + 25x + 110 + 85 --> group like terms
40x + 195 --> add like terms
p(x) + q(x) = 40x + 195 --> This is the function that represents the total profit for January and February
4 0
2 years ago
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According to a study conducted by the Toronto-based social media analytics firm Sysomos, 71% of all tweets get no reaction. That
timama [110]

Answer:

Let X the random variable of interest "number of tweets with no reaction", on this case we now that:

X \sim Binom(n=100, p=0.71)

And the expected value is given by:

E(X) = np =100*0.71 = 71

So we expect about 71 tweets with no reaction for this case.

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

Solution to the problem

Let X the random variable of interest "number of tweets with no reaction", on this case we now that:

X \sim Binom(n=100, p=0.71)

And the expected value is given by:

E(X) = np =100*0.71 = 71

So we expect about 71 tweets with no reaction for this case.

3 0
2 years ago
Suppose you roll a pair of honest dice. If you roll a total of 7 you win $22, if you roll a total of 11 you win $66, if you roll
JulijaS [17]

Answer:

The expected payoff for this game is -$1.22.

Step-by-step explanation:

It is given that a pair of honest dice is rolled.

Possible outcomes for a dice = 1,2,3,4,5,6

Two dices are rolled then the total number of outcomes = 6 × 6 = 36.

\{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),\\(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),\\(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)\}

The possible ways of getting a total of 7,

{ (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) }

Number of favorable outcomes = 7

Formula for probability:

Probability=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}

So, the possibility of getting a total of 7 = \frac{6}{36}=\frac{1}{6}

The possible ways of getting a total of 11,

{(5,6), (6,5)}

So, the probability of getting a total of 11 = \frac{2}{36} = \frac{1}{18}

Now, other possible rolls = 36 - 6 - 2 = 36 - 8 = 28,

So, the probability of getting the sum of numbers other than 7 or 11 = \frac{28}{36} = \frac{7}{9}

Since, for the sum of 7, $ 22 will earn, for the sum of 11, $ 66 will earn while for any other total loss is $11,

Hence, the expected value for this game is

\frac{1}{6}\times 22+\frac{1}{18}\times 66-\frac{7}{9}\times 11

\frac{11}{3}+\frac{11}{3}-\frac{77}{9}

\frac{22}{3}-\frac{77}{9}

\frac{66-77}{9}

-\frac{11}{9}

-1.22

Therefore the expected payoff for this game is -$1.22.

4 0
2 years ago
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