Question

Consider a process carried out on 1.00 mol of a monatomic ideal gas by the following two different pathways.

Answer 1

Answer:

90 L.atm

Explanation:

From the given information:

The first pathway:

A( 3 atm, 20 L) → C ( 1 atm, 20 L) → D (1 atm, 50 L)

The second pathway:

A(3 atm, 20 L) → B( 3 atm, 50 L) → D ( 1 atm, 50 L)

Since the number of moles = 1.00 moles

To find wAB;

A → B  shows the conversion happening at constant pressure ;

∴

wAB = pressure × volume change

wAB = P(V₂ - V₁)

wAB =  3 atm ( 50 L - 20 L)

wAB =  3 atm ( 30 L)

wAB = 90 L.atm