Answer:
option B.
Explanation:
The correct answer is option B.
Principal stress is the maximum normal stress a body can have. In principal stress, there is purely normal stress. On principal plane shear stress is zero.
In-plane shear stress are the shear stress which is acting on the plane.
The statement which is correct regarding principle plane and shear stress is that The shear stress over principal stress planes is always zero.
Answer:
Given data
w1/w2=6.5/1
Power=5 KW
wp=1800 rpm
angle=14 degrees
Based on above values,the minimum diameter=30 mm
Click I think:) not sure tho
Answer:
Ψ = 10(y^2) + c
<em><u>y = 1.067m</u></em>
Explanation:
since the flow is one dimensional in positive X direction, the only velocity component is in X, which is denoted by u
while u is a function of y
we find the u in terms of y; u varies linearly wih y
we use similiraty to find the relation
32/1.6 =<em>u/y</em>
<em><u>u = 20y</u></em>
<em><u>Ψ = ∫20ydy</u></em>
<em><u>Ψ = 10(y^2) + c</u></em>
<em><u>(b)</u></em>
<em><u>the flow is half below y = 1.6*(2/3)=1.067 m</u></em>
<em><u>this is because at two third of the height of a triangle lies the centroid of triangle. since the velocity profile forms a right angled triangle , its height is 1.6 m . the flow is halved at y = 1.067m</u></em>
