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Darina [25.2K]
2 years ago
12

1. A spur gear made of bronze drives a mid steel pinion with angular velocity ratio of 13 /2 : 1. Thepressure angle is 14 1/2° .

It transmits 5 kW at 1800 r.p.m. of pinion. Considering only strength, design the smallest diameter gears and find also necessary face width. The number of teeth should not be less than 15 teeth on either gear. The elastic strength of bronze may be taken as 84 MPa and of steel as 105 MPa. Lewis factor for 14 1/2° pressure angle may be taken as y =0.6840.124 –No. of teeth.
Engineering
1 answer:
Alik [6]2 years ago
5 0

Answer:

Given data

w1/w2=6.5/1

Power=5 KW

wp=1800 rpm

angle=14 degrees

Based on above values,the minimum diameter=30 mm

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The rigid bar CDE is attached to a pin support at E and rests on the 30 mm diameter brass cylinder BD. A 22 mm diameter steel ro
Leno4ka [110]

Answer:

stress = 38.84 MPa

Explanation:

S_{D} = \alpha _{brass} * (delta T) *(L_{BD} )\\= (18.8 * 10^(-6) )*(30)*(0.3)\\= 0.0001692 m\\\\E_{BD} = stress / strain\\stress = E_{BD} * S_{D}\\stress = (200 *10^9) * (0.0001692)\\stress = 33.84 MPa

3 0
2 years ago
While at a concert you notice five people in the crowd headed in the same direction. Your tendency to group them is due to? *
Vlada [557]

Answer:

common fate

Explanation:

The gestalt effect may be defined as the ability of our brain to generate the whole forms from the groupings of lines, points, curves and shapes. Gestalt theory lays emphasis on the fact that whole of anything is much greater than the parts.

Some of the principles of Gestalt theory are proximity, similarity, closure, symmetry & order, figure or ground and common fate.

Common fate : According to this principle, people will tend to group things together which are pointed towards or moving in a same direction. It is the perception of the people that objects moving together belongs together.

7 0
2 years ago
The uniform 8–ft board is pushed down into the water so it makes an angle of θ = 30o with the water surface. If the cross sectio
lana66690 [7]

Answer:

The vertical force, F = 19.9 lb.

Explanation:

3 0
2 years ago
Python Homework
DerKrebs [107]

Answer:

  1. TAX_RATE = 0.20
  2. STANDARD_DEDUCTION = 10000.0
  3. DEPENDENT_DEDUCTION = 3000.0
  4. # Request the inputs
  5. grossIncome = float(input("Enter the gross income: "))
  6. numDependents = int(input("Enter the number of dependents: "))
  7. # Compute the income tax
  8. taxableIncome = grossIncome - STANDARD_DEDUCTION - \
  9. DEPENDENT_DEDUCTION * numDependents
  10. incomeTax = taxableIncome * TAX_RATE
  11. # Display the income tax
  12. print("The income tax is $" + str(round(incomeTax,2)))

Explanation:

We can use round function to enable the program to output number with two digits of precision.

The round function will take two inputs, which is the value intended to be rounded and the number of digits of precision. If we set 2 as second input, the round function will round the incomeTax to two decimal places. The round function has to be enclosed within the str function so that the rounded value will be converted to a string and joined with the another string to display the complete a sentence of income tax info.

5 0
2 years ago
Steam enters a turbine operating at steady state at 1 MPa, 200 °C and exits at 40 °C with a quality of 83%. Stray heat transfer
Andrei [34K]

Answer:

(a) Work out put=692.83\frac{KJ}{Kg}

(b) Change in specific entropy=0.0044\frac{KJ}{Kg-K}

Explanation:

Properties of steam at 1 MPa and 200°C

        h_1=2827.4\frac{KJ}{Kg},s_1=6.69\frac{KJ}{Kg-K}

We know that if we know only one property in side the dome then we will find the other property by using steam property table.

Given that dryness or quality of steam at the exit of turbine is 0.83 and temperature T=40°C.So from steam table we can find pressure corresponding to saturation temperature 40°C.

Properties of saturated steam at 40°C

      h_f= 167.5\frac{KJ}{Kg} ,h_g= 2537.4\frac{KJ}{Kg}

 s_f= 0.57\frac{KJ}{Kg-K} ,s_g= 8.25\frac{KJ}{Kg-K}

So the enthalpy of steam at the exit of turbine  

h_2=h_f+x(h_g-h_f)\frac{KJ}{Kg}

h_2=167.5+0.83(2537.4-167.5)\frac{KJ}{Kg}

h_2=2134.57\frac{KJ}{Kg}

s_2=s_f+x(s_g-s_f)\frac{KJ}{Kg-K}

s_2=0.57+0.83(8.25-0.57)\frac{KJ}{Kg-K}

s_2=6.6944\frac{KJ}{Kg-K}

(a)

Work out put =h_1-h_2

                      =2827.4-2134.57 \frac{KJ}{Kg}

Work out put =692.83 \frac{KJ}{Kg}

(b) Change in specific entropy

     s_2-s_1=6.6944-6.69\frac{KJ}{Kg-K}

Change in specific entropy =0.0044\frac{KJ}{Kg-K}

3 0
2 years ago
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