<u>Given:</u>
Present population of bison = 3652
Maximum growth rate = 0.28
<u>To find:</u>
The population of bison after one year.
<u>Solution:</u>
The future population can be calculated with the help of the following formula,
where 
is the future population, 
is the present population, r is the growth rate and n is the number of years.
On substituting the given values in the formula we get,
Therefore, the population size of bison after one year is 4675. The park does not have to control the population because the growth rate is on an average scale.
Answer:
D. 1 BB : 2 Bb : 1 bb
Explanation:
This question involves a single gene coding for fur color in guinea pig. Black fur (B) is dominant over white fur (b). This means that, as stated in the question, if a black fur parent (BB) is crossed with a white fur parent (bb), a 100% heterozygous offspring (Bb) with black fur will result.
If two heterozygous guinea pigs are crossed i.e. Bb × Bb, the following gametes will be produced by each heterozygous parent:
Bb = B and b
Using these gametes in a punnet square (see attached image), offsprings with the following genotypic ratio will be produced:
1 BB : 2 Bb : 1 bb
BB and Bb = black fur guinea pigs
bb = white fur guinea pigs
True because I am going to become pirate king and find ONE PIECE. lol! Great anime I suugest to everyone!
*The key function of each of the two photosystems is to absorb light and convert the energy of the absorbed light into redox energy, which drives electron transport.
In PS II (the first photosystem in the sequence), P680 is oxidized (which in turn oxidizes water), and the PS II primary electron acceptor is reduced (which in turn reduces the electron transport chain between the photosystems).
In PS I, the PS I primary electron acceptor is reduced (which in turn reduces other compounds that ultimately reduce NADP+ to NADPH), and P700 is oxidized (which in turn oxidizes the electron transport chain between the photosystems).
Answer:
I might be wrong but im guessing 600
Explanation:
Since there is one molecule of glucose used per 6 molecules of carbon dioxide released, if you have 100 molecules of glucose, then you multiply the carbon dioxide by 100 which is 600. Thats what I would say but I might be wrong.
