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MArishka [77]
1 year ago
13

Build a schedule for the following staffing requirements, giving workers two consecutive days off per cycle (not including Sunda

y). Assume that 4 days of work is full time.
Day Mon Tue Wed Thu Fri Sat
Staff needed 3 4 2 3 4 5
Business
1 answer:
jasenka [17]1 year ago
6 0

Answer:

Explanation:

The following process is used to schedule staffing requirements.

Start appointing workers in a way that two days contain the lowest amount of staff required are designated first.

Then, we minus 1 from each cell except for the selected pair of days.

After that, we lookout for pairs of days that contain the least amount of staff requirements.

We will then repeat the above process until the staffing requirements are fully met.

OUTPUT:

\ A\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B\ \ \ \ \ \ \ \ \ \ \ C\ \ \ \ \ \ \ \ \ \ \ D\ \ \ \ \ \ \ \ \ \ \ E\ \ \ \ \ \ \ \ \ \ \ F\ \ \ \ \ \ \ \ \ \ \ G

1 \ \ \      \ Day \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Mon \ \ \ \ \ \ \ \ \ \ \  Tue \ \ \ \ \ \ \ \ \ \ \ Wed \ \ \ \ \ \ \ \ \ \ \  Thur \ \ \ \ \ \ \ \ \ \ \ Fri \ \ \ \ \ \ \ \ \ \ \ Sat

2 \ \ \      \ Staff \ needed  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3 \ \ \ \ \ \ \ \ \ \ \  4 \ \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ \ \ \ \  3 \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \ 5

3 \ \ \      \ Worker \ 1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3 \ \ \ \ \ \ \ \ \ \ \  4 \ \ \ \ \ \ \ \ \ \ \ \mathbf{2 \ \ \ \ \ \ \ \ \ \ \  3} \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \ 5      

4 \ \ \      \ Worker \ 2 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \mathbf{ 2 \ \ \ \ \ \ \ \ \ \ \  3} \ \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ \ \ \ \  3 \ \ \ \ \ \ \ \ \ \ 3 \ \ \ \ \ \ \ \ \ \ \ 4

5 \ \ \      \ Worker \ 3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ \ \ \ \  3 \ \ \ \ \ \ \ \ \ \ \ \mathbf{1 \ \ \ \ \ \ \ \ \ \ \  2} \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ \ \ \ \ 3    

6 \ \ \      \ Worker \ 4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1 \ \ \ \ \ \ \ \ \ \ \  2 \ \ \ \ \ \ \ \ \ \ \ \mathbf{1 \ \ \ \ \ \ \ \ \ \ \  2} \ \ \ \ \ \ \ \ \ \ 1 \ \ \ \ \ \ \ \ \ \ \ 2

7 \ \ \      \ Worker \ 5 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0 \ \ \ \ \ \ \ \ \ \ \  1 \ \ \ \ \ \ \ \ \ \ \ 1 \ \ \ \ \ \ \ \ \ \ \  2 \ \ \ \ \ \ \ \ \ \ \mathbf{0 \ \ \ \ \ \ \ \ \ \ \ 1}

8 \ \ \      \ Worker \ 6 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0 \ \ \ \ \ \ \ \ \ \ \  0 \ \ \ \ \ \ \ \ \ \ \ 0 \ \ \ \ \ \ \ \ \ \ \  1 \ \ \ \ \ \ \ \ \ \ \ 0 \ \ \ \ \ \ \ \ \ \ \ 1

9 \ \ \      \ No \ working^* \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3 \ \ \ \ \ \ \ \ \ \ \  4 \ \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ \ \ \ \  3 \ \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \ 5

10    *count the number of workers after excluding highlighted cells and 0 values.

Day      Minimum number of workers needed

Mon     \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \     3

Tue  \ \ \ \ \ \ \ \ \   \  \ \ \ \ \ \ \ 4

Wed  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2

Thur  \ \ \ \ \ \ \ \ \ \ \  \ \ \ 3

Fri  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 4

Sat  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 5

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Tim spends his income on donuts (D) and coffee (C). Coffee is $2 per cup and donuts are $1 each. Assume that Tim has $10 to spen
stealth61 [152]

Answer:

Optimal number of donuts = 5 Donuts

Optimal cups of coffee = 2.5 cups.

Explanation:

Optimal numbers of donuts and coffee can be calculated as follow

First, we need to determine the budget constraint as below

M = ( P(D) x D ) + ( P(C) x C )

Placig values in the formula

10 = D + 2C

Now make utility function as:

U(D,C) = D0.5 C0.5

Marginal Utility donuts

MU(D) = 0.5D-0.5C0.5

Marginal Utility Coffee

MU(C) = 0.5D0.5C-0.5

The formula for marginal rate of substitution

(MRSD,C)= MU(D) / MU(C)  = 0.5D - 0.5C0.5 / 0.5D0.5C - 0.5  = C/D

Now calculate the optimal consumption level  

MRSD,C = P(D) / P(C)

C/D = 1/2

D = 2C (Equation 1 )

Placing the value of D resulted from equation 1, in the budget constraint we as below

10 = D + 2C

10 = 2C + 2C

10 = 4C

C = 10/4 = 2.5

NOw place the value of C in equation 1

D = 2C = 2(2.5) = 5

Optimal number of donuts = 5 Donuts

Optimal cups of coffee = 2.5 cups.

7 0
1 year ago
At the beginning of 2019, Robotics Inc. acquired a manufacturing facility for $13.5 million. $10.5 million of the purchase price
sdas [7]

Answer:

$511,667

Explanation:

The computation of the depreciation expense for 2019 and 2020 is shown below:

= (Purchase price - residual value) ÷ (useful life)

= ($10,500,000 - $2,500,000) ÷ (25 years)

= ($8,000,000) ÷ (25 years)  

= $320,000

The depreciation in this method is the same for the rest of the useful life

Now the book value for 2021 would be

= Purchase price - depreciation for 2 years

= $10,500,000 - $320,000 × 2

= $9,860,000

Now the depreciation for 2021 would be

= ($9,860,000 - $650,000) ÷ 18 years

= $511,667

3 0
1 year ago
Gordon Corporation produced 10,000 digital watches in the current year. Variable costs are $8 per watch. Overhead assigned is $2
olchik [2.2K]

Answer:b

Explanation:sorry if the answer is wrong

8 0
1 year ago
Berry, the seller, wants Paul, the broker, to change from a single agency relationship to a transaction broker. Paul agrees to d
Scorpion4ik [409]

Answer:

Before the listing agreement is signed.

Explanation:

A listing agreement is a contract between a property owner and a real estate broker asking the real estate broker to get a buyer for his or her property. The property owner implements the listing agreement so as to empower the real estate broker to act in the capacity of the agent to the owner in the course of trying to sell the property. Generally certain commission is paid to the real estate broker by the property owner.

8 0
1 year ago
On January 1, Year 1, Sayers Company issued $280,000 of five-year, 6 percent bonds at 102. Interest is payable semiannually on J
mel-nik [20]

Answer:

The cash received from bond issuance is journalized as follows:

Dr Cash                                $285,600

Cr  Bonds payable                                  $280,000

Cr Premium on Bonds payable                   $5,600

The June 30 and 31 December Year 1 interest on the bonds are recorded thus:

30 June

Dr Interest expense(bal fig) $7,840                                          

Dr Premium on bonds           $560

Cr Cash                                         $8400

31 December

Dr Interest expense(bal fig) $7,840                                          

Dr Premium on bonds           $560

Cr Cash                                         $8400

The June 30 and 31 December Year 2 interest on the bonds are recorded thus:

30 June

Dr Interest expense(bal fig) $7,840                                          

Dr Premium on bonds           $560

Cr Cash                                             $8400

31 December

Dr Interest expense(bal fig) $7,840                                          

Dr Premium on bonds           $560

Cr Cash                                            $8400

Explanation:

The amount realized from the bond is calculated thus:

$280,000*102%=$285,600

Premium on  bond=Bonds proceeds-par value

                                =$285,600-$280,000

                                =$5,600

Semi-annual amortization of bond premium=$5,600/5*6/12

                                                                         =$560

Semi-annual interest payment=$280,000*6%*6/12

                                                 =$8,400

5 0
1 year ago
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