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AlladinOne [14]

2 years ago

11

How many solutions does the system have? \begin{cases} 3x+y=8 \\\\ 2x+2y=8 \end{cases} ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ 3x+y=8 2x+2y=8 Choose 1

answer: Choose 1 answer: (Choice A, Checked) A Exactly one solution (Choice B) B No solutions (Choice C) C Infinitely many solutions

1 answer:

ELEN [110]2 years ago

3 0

Answer:

This system has one solution (x=2 and y=2), then the answer is A.

Step-by-step explanation:

The system of equations is:

$3x+y=8$ (1)

$2x+2y=8$ (2)

Let's multiply the first equation by 2 and subtract it to the second equation

$6x-2x+2y-2y=16-8$

$4x=8$

$x=2$

Using this value in (1) we can find y.

$3(2)+y=8$

$6+y=8$

$y=2$

Therefore, this system has one solution (x=2 and y=2), the answer is A.

I hope it helps you!

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A farmer has 13 cows. a bolt of lightning kills all but 5 of them. how many cows survived?

jeyben [28]

<span>Given that a farmer has 13 cows if a bolt of lightning kills all but 5 of them, this means that the bolt of lightning killed all the cows except 5.

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2 years ago

A salesman normally makes a sale (closes) on % of his presentations. Assuming the presentations are independent, find the pro

Tamiku [17]

Answer:

$(a)\ 0.0864$

$(b)\ 0.096$

$(c)\ 0.24$

$(d)\ 0.936$

Step-by-step explanation:

Given

$p \to$ close

$q \to$ fail to close

$p = 60\%$

$p = 0.60$

First, calculate the value of q

Using complement rule

$q = 1 - p$

$q = 1 - 0.60$

$q = 0.40$

So, we have:

$p = 0.60$ and $q = 0.40$

Solving (a): Fails to close on the 4th attempt

This means that he closes the first three attempts. The event is represented as: p p p q

So, we have:

$Pr = p*p*p*q$

$Pr = p^3*q$

$Pr = 0.60^3*0.40$

$Pr = 0.0864$

Solving (b): He closes for the first time on the 3rd attempt

This means that he fails to close the first two attempts. The event is represented as: q q p

So, we have:

$Pr = q * q * p$

$Pr = q^2 * p$

$Pr = 0.40^2 * 0.60$

$Pr = 0.096$

Solving (c): First he closes is his 2nd attempt

This means that he fails to close the first. The event is represented as: q p

So, we have:

$Pr = q * p$

$Pr = 0.40 * 0.60$

$Pr = 0.24$

Solving (d): The first he close is one of his 3 attempts

To do this, we make use of complement rule

The event that he does not close any of his first three attempts is: q q q

The probability is:

$Pr = q*q*q$

$Pr = q^3$

The opposite is that the first he closes is one of the first three

So, we have:

$Pr' = 1- Pr$ --- complement rule

$Pr' = 1- q^3$

$Pr' = 1- 0.40^3$

$Pr' = 1- 0.064$

$Pr' = 0.936$

4 0

2 years ago

Which statement describes 4/7 x 3/5?

Nataly [62]

Answer:

0.34285714285 i think

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

What is the product of a+3 and −2a2+15a+6b2?

rewona [7]

For this case we must find the product of the following expression:

$(a + 3) (- 2a ^ 2 + 15a + 6b ^ 2)$

We apply distributive property term to term:

$(a + 3) (- 2a ^ 2 + 15a + 6b ^ 2) =\\-2a ^ 2 * a + 15a * a + 6b ^ 2 * a-6a ^ 2 + 45a + 18b ^ 2 =\\-2a ^ 3 + 15a ^ 2 + 6ab ^ 2-6a ^ 2 + 45a + 18b ^ 2=$

We add similar terms:

$-2a ^ 3 + (15-6) a ^ 2 + 6ab ^ 2 + 45a + 18b ^ 2 =\\-2a ^ 3 + 9a ^ 2 + 6ab ^ 2 + 45a + 18b ^ 2 =$

Finally, the expression is as:

$-2a ^ 3 + 9a ^ 2 + 6ab ^ 2 + 45a + 18b ^ 2$

Answeer:

$-2a ^ 3 + 9a ^ 2 + 6ab ^ 2 + 45a + 18b ^ 2$

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2 years ago