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2 years ago

5

Alison wants to distribute the carnations and roses equally among the 6 flower shops. Generate an equivalent expression from que

stion 1, using Distributive Property where 6 is the common factor.

1 answer:

boyakko [2]2 years ago

3 0

How many carnations and roses are there?

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The table shows different quantities of flour and the number of cookies that can be made with each quantity of flour. If the rel

nirvana33 [79]

3/4 = 6/x....3/4 = 6/8...notice that proportions are nothing but equivalent fractions

x = 8

4 0

2 years ago

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A random number generator is used to create a list of 150 single-digit numbers. Of those 150 numbers, 72 are odd and 78 are even

Artemon [7]

Answer:

38%

Step-by-step explanation:

Option: 38%.

Total number of numbers: 150

Number of odd numbers: 72

Number of nines: 15

Number of odd numbers other than nine: 72 - 15 = 57

Probability = [number of odd numbers other than nine] / [total number of numbers] = 57/150 = 0.38

0.38 = 38%

4 0

2 years ago

Javier is 175% heavier than his brother. If Javier’s brother weighs 80 pounds, how much does Javier weigh?

777dan777 [17]

Let us say weight of Javier is x pounds.

Weight of his bother = 80 pounds

Javier is 175 % or 1.75 times heavier than his brother.

So Javier's weight = x pounds= 1.75 *80 = 140 pounds.

Answer: Javier's weight is 140 pounds.

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2 years ago

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A tank contains 500 gallons of salt-free water. A brine containing 0.25 lb of salt per gallon runs into the tank at the rate of

Neporo4naja [7]

Answer:

0.0198 lbs per gallon

Step-by-step explanation:

amount of salt free water = 500 gallons

salt rate in = 1 gal/min

salt rate out = 1 gal/min

amount o salt in brine = 0.25 lb per gallon

Let the amount of salt in the tank be A(t) at any time t.

$\frac{dA(t)}{dt} =salt rate in - salt rate out$

salt rate in = 0.25 x 1 = 0.25

salt rate out = $\frac{A(t)\times 1}{500}$

The differential equation is given by

$\frac{dA(t)}{dt} =1 - \frac{A(t)\times 1}{500}$

where, A(0) = 0

So, the equation becomes

$\frac{dA(t)}{dt} + \frac{A(t)}{500} = 1$

Here the integrating factor is $e^{\frac{dt}{500}}=e^{\frac{t}{500}}$

The solution of the above differential equation is given by

$A(t)\times e^{\frac{t}{500}} = \int e^{\frac{t}{500}}dt$

$A(t)\times e^{\frac{t}{500}} = 500\times e^{\frac{t}{500}}+C$

where, C is the integrating constant.

$A(t)=500+Ce^{-\frac{t}{500}}$

Put, A(0) = 0

C = - 500

$A(t)=500\left ( 1-e^{-\frac{t}{500} \right )$

As concentration is defined as

Concentration = Quantity / Volume

$C(t)=\frac{A(t)}{500}$

$C(t)=1-e^{\frac{-t}{500}}$

Now concentration at t = 10 min

Put, t = 10 min

$C(10)=1-e^{\frac{-10}{500}}$

C (10) = 0.0198 lbs per gallon

Thus, teh concentration after 10 min is 0.0198 lbs per gallon.

7 0

2 years ago

Sarah wants to print copies of her artwork. At the local print shop, it costs her $1 to make 5 copies and $5 to make 25 copies.

Ierofanga [76]

Answer:

i wanna say B

Step-by-step explanation:

6 0

2 years ago

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