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melamori03 [73]
1 year ago
12

An ISP is granted the block 16.12.64.0/20. The ISP needs to allocate addresses for 8 organizations, each with 256 addresses. a.

Find the number and range of addresses in the ISP block. b. Find the range of addresses for each organization and the range of unallocated addresses. c. Show the outline of the address distribution and the forwarding table.
Computers and Technology
1 answer:
melisa1 [442]1 year ago
8 0

Answer:

I did not understand a thing from your writing

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We have an internal webserver, used only for testing purposes, at IP address 5.6.7.8 on our internal corporate network. The pack
lukranit [14]

Answer:

Check the explanation

Explanation:

A packet filter firewall is used as a check point between internal corporate network to the outside internet. It blocks all the inbound traffic from the outside hosts trying to initiate a direct TCP connection to the internal corporate webserver. The network design with firewall is shown in the attached image below:

The figures in the attached image below shows an internal corporate network is protected with a packet filter firewall to minimize the inbound traffic from the external network or an internet. Therefore, the packet filter is used as a check point between the network.

The packet filter blocks all attempts by the outside hosts in order to initiate a direct TCP connection to the internal webserver of the internal corporate network.

Going by the second part of the attached image below can can therefore conclude that:

• Rule 1 specifies that, deny any packet with the destination address 5.6.7.8 if the STN flag of TCP header is set.

• Rule 2 specifies that, allow the inbound email traffic from the external source.

• Rule 3 specifies, allows the Outbound TCP traffic from the internal corporate network.

• Rule 4 specifies, allows outbound Email traffic from the internal corporate network to the external network.

• Rule 5 specifies, block any traffic from any source to the any destination.

3 0
1 year ago
Light travels at 3 × 108 meters per second. A light-year is the distance a light beam travels in one year.Write a PYTHON program
Art [367]

Answer: This is a python code

def lightyear():

   rate=3*100000000   //speed of light

   seconds=365*24*60*60   //number of seconds in 1 year

   return str((rate*seconds)/1000)+" km"    //distance=speed x time

print(lightyear()) //will print value of light hear in kilometers

OUTPUT :

9460800000000.0 km

Explanation:

In the above code, there is a variable rate, which stores the speed of light, i.e. distance traveled by light in 1 second which is in meters. Another variable is seconds, which store the number of seconds in 1 year, which is no of days in 1 year multiplied by the number of hours in a day multiplied by the number of minutes in an hour multiplied by the number of seconds in a minute. Finally, distance is speed multiplied by time, so distance is printed in kilometers and to convert distance in kilometers it is divided by 1000.

4 0
1 year ago
Which data type change will require the app builder to perform the additional steps in order to retain existing functionalities?
Readme [11.4K]

Answer:

Option D is the correct option.

Explanation:

The following option is correct because the lead alteration from number to text and the number to text types of data will reconstruct the important number of the app builder to accomplish those steps which is extra to continue to have that functionality which is in the existence. That's why the app builder has to be reconstructed the types of data for the custom fields.

7 0
1 year ago
Assign max_sum with the greater of num_a and num_b, PLUS the greater of num_y and num_z. Use just one statement. Hint: Call find
Gnoma [55]

Answer:

def find_max(num_1, num_2):

   max_val = 0.0

   if (num_1 > num_2): # if num1 is greater than num2,

       max_val = num_1 # then num1 is the maxVal.

   else: # Otherwise,

       max_val = num_2 # num2 is the maxVal

   return max_val

max_sum = 0.0

num_a = float(input())

num_b = float(input())

num_y = float(input())

num_z = float(input())

max_sum = find_max(num_a, num_b) + find_max(num_y, num_z)

print('max_sum is:', max_sum)

Explanation:

I added the missing part. Also, you forgot the put parentheses. I highlighted all.

To find the max_sum, you need to call the find_max twice and sum the result of these. In the first call, use the parameters num_a and num_b (This will give you greater among them). In the second call, use the parameters num_y and num_z (This will again give you greater among them)

5 0
1 year ago
Match common encryption algorithms and methods with the scenarios representing real-world business applications and requirements
Sladkaya [172]

The question is incomplete as the scenarios are not given that were to be matched by the given encryption algorithms.

By finding the question from internet i have attached the image of the scenarios in the form of table and answered below accordingly

<h2>Answer:</h2>

<u>Scenario A:</u>

Advanced Encryption Standard (AES) is a technique that uses 256-bit cipher texts for encryption process. The data encrypted by AES cannot be attacked and even it cannot be decrypted unless a brute-force search is used through all of possible 256-bit keys.For mobile security it is known as one of the best algorithms.

<u>Scenario B:</u>

Following are the techniques of encryption used for given scenario:

  • ECC
  • Digital Signature
  • AES
  • Blowfish

<u>Scenario C:</u>

Following are the techniques of encryption used for given scenario:

  • ECC
  • Blowfish

<u>Scenario D:</u>

Secure Sockets Layer (SSL) - SSL is a protocol that is commonly-used for managment of the message transmission security over the Internet)

<u>Scenario E:</u>

Advanced Encryption Standard (AES) - AES is an encryption algorithm used by U.S. Government agencies for securing sensitive but unclassified material .

i hope it will help you!

5 0
1 year ago
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